Conservation of Energy + Projectile Motion

AI Thread Summary
The discussion revolves around calculating the height from which a ball must roll down a ramp to land in a hole 100 cm away and 0.05 cm deep, using conservation of energy and projectile motion equations. The user initially derives the launch velocity but encounters confusion regarding negative height results and the mixing of units between centimeters and meters. Clarifications are made about the time calculation and the correct application of formulas, emphasizing the importance of consistent units. The overall approach using conservation of energy to find launch velocity is deemed acceptable, though algebraic errors are suspected. The user expresses gratitude for the assistance and seeks confirmation on their method.
andy343
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Homework Statement


So I have a ball rolling down a ramp structure from rest and up a curve,to launch out at 15 degrees. The ball lands 100cm away in a hole 0.05cm deep.
The height in which it comes out of the ramp is 0.05cm high
angle at which ball launches out = 15 degrees above horiontal
dx=100cm
dy=-0.05+-0.05= -0.1cm
*also the lowest point of the ramp is on the ground

find the height in which the ball needs to be rolled down the ramp in order to land 100cm away and into a hole 0.05cm deep.

Homework Equations


Conservation of energy
projectile motion equations

The Attempt at a Solution


Use conservation of energy equation to find velocity and than input that into dy=vyit+1/2ayt^2
Ei=Ef
Ei=KEt+KEr
mgh=1/2mv^2+1/2Iw^2
I=2/5mr^2
w=v/r
mgh=7/10mv^2
solve for v, v=sqrt(10/7gh)---= launching velocity
Use formula dy=vyit+1/2ayt^2
t=dx/vx
vx=cos(15)vi
vyi=sin(15)vi
-0.1=sin15vi(100/cos15vi)+1/2(-9.81)(1/(cos15)(vi))^2
vi cancels vi=launching velocity = sqrt(10/7gh)
-0.1=sin15(100/cos15)+1/2(-9.81)(100^2/(cos15)^2(10/7(9.81)h)
9.81 cancels
-0.1=sin15(100/cos15)+1/2(-1)(100^2/(cos15)^2(10/7h)
solve for h
h=-70.9cm
Umm, I don't get why my height becomes negative..so I think I did something wrong but
I don't know where. ---This is actually from my lab and not a problem so I might be missing something.
 
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I'm slightly confused about what the 100/cos15 is. Is that your time?
 
Um oh sorry about the confusion...I accidently inputed some wrong numbers, give me a second
and yes that is my time
 
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Where does "100" come from?
 
So it lands in a hole 100cm* away in 0.05cm* deep hole.
 
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You can't mix meters and centimeters in one formula. "9.81" is in meters.
 
lol, okay I think I know why my calculations are wrong now...my bad
TYVM
One more thing, so am I approaching the calculation/problem correctly? by using conservation of energy to find launch velocity and than input that into the dy=vyit+1/2ayt^2?
 
The overall approach seems OK. There might be errors in algebra - the formulas are very hard to read.
 
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