andy343
- 6
- 0
Homework Statement
So I have a ball rolling down a ramp structure from rest and up a curve,to launch out at 15 degrees. The ball lands 100cm away in a hole 0.05cm deep.
The height in which it comes out of the ramp is 0.05cm high
angle at which ball launches out = 15 degrees above horiontal
dx=100cm
dy=-0.05+-0.05= -0.1cm
*also the lowest point of the ramp is on the ground
find the height in which the ball needs to be rolled down the ramp in order to land 100cm away and into a hole 0.05cm deep.
Homework Equations
Conservation of energy
projectile motion equations
The Attempt at a Solution
Use conservation of energy equation to find velocity and than input that into dy=vyit+1/2ayt^2
Ei=Ef
Ei=KEt+KEr
mgh=1/2mv^2+1/2Iw^2
I=2/5mr^2
w=v/r
mgh=7/10mv^2
solve for v, v=sqrt(10/7gh)---= launching velocity
Use formula dy=vyit+1/2ayt^2
t=dx/vx
vx=cos(15)vi
vyi=sin(15)vi
-0.1=sin15vi(100/cos15vi)+1/2(-9.81)(1/(cos15)(vi))^2
vi cancels vi=launching velocity = sqrt(10/7gh)
-0.1=sin15(100/cos15)+1/2(-9.81)(100^2/(cos15)^2(10/7(9.81)h)
9.81 cancels
-0.1=sin15(100/cos15)+1/2(-1)(100^2/(cos15)^2(10/7h)
solve for h
h=-70.9cm
Umm, I don't get why my height becomes negative..so I think I did something wrong but
I don't know where. ---This is actually from my lab and not a problem so I might be missing something.
Last edited: