Conservation of Energy with Spring and Incline (Diagram Included)

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SUMMARY

The discussion focuses on the conservation of energy involving elastic potential energy in a spring system on an incline. The participant utilized the equation ET = 1/2(m)(V²) + mgh + 1/2k*x² to analyze energy transformations. An error arose when calculating work done against friction (Wf), leading to a negative value under the square root. The participant concluded that the height can be considered negligible, as it cancels out in the energy equation.

PREREQUISITES
  • Understanding of elastic potential energy and the spring constant (k)
  • Familiarity with gravitational potential energy (mgh)
  • Knowledge of work-energy principles, particularly in inclined planes
  • Basic algebra skills for manipulating equations and solving for variables
NEXT STEPS
  • Review the derivation of the work-energy principle in inclined planes
  • Study the effects of friction on energy conservation in mechanical systems
  • Learn about the implications of negative values in physical equations
  • Explore the concept of energy conservation in elastic collisions
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, energy conservation, and inclined plane problems. This discussion is beneficial for anyone tackling similar homework or projects involving springs and energy transformations.

Wara
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Elastic Potential Energy with Spring and Incline (Diagram Included)

Homework Statement


04.21.2012-17.21.10.png



Homework Equations


ET = 1/2(m)(V2) + mgh + 1/2k*x2


The Attempt at a Solution


ET1 - Wf = ET2
1/2k*x2 - Wf = mgh + 1/2mV2

where, Wf = [(0.53)(2kg)(9.8m/s2)(cos67)](1.3m+0.4m)

^ I used this formula and went through by subbing in all numbers but I get error since you can't square root a negative value. Plus we can assume Height off ground is negligible since it cancels out on both sides of equation.
 
Last edited:
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does anyone know why I'm getting that negative error? Is my formula correct?
 

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