1. A spring of constant 22 N/m is compressed a distance 8 cm by a 0.4kg mass, then released. It skids over a frictional surface of length 2.3m with coefficient of friction 0.17, then compresses the second spring of constant 2N/cm. The acceleration of gravity is 9.8m/s(squared). How far will the second spring cmpress in order to bring the mass to a stop? Answer in cm. 2. W=Fd .5mgyf + .5Kdelta(X squared) = .5mgyo + .5Kdelta(Xsquared) also mgyf + 1/2mVf^2 = mgyo + 1/2mVo^2 3. I used all three formulas but the fact that I'm using cefficients is throwing me off.