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astro2525
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Homework Statement
A 5-gram bullet is shot horizontally at a 2-kg wooden block resting against a relaxed 100 N/m spring (the other end of the spring is fixed against a wall, the spring and the block sitting on a horizontal, frictionless table). It is observed that the bullet bounces back at 50 m/s and that the spring shows a maximal compression of 5-cm.
A) What was the initial speed of the bullet?
B) What fraction of the initial kinetic energy of the bullet was lost during the collision?
m of bullet = .005 kg
M of wooden block = 2 kg
Vfinal of bullet = 50 m/s
Max compression (x) = 5-cm = .05 m
Homework Equations
Looks like elastic collision so .. total momentum is conserved as well as kinetic energy.
KE = (1/2)m*v^2
EPE = (1/2)k*x^2
The Attempt at a Solution
When spring is completely compressed:
KEinitial(bullet) = PE(spring) + KEfinal(bullet)
(1/2).005*v^2 = (1/2)*100*.05^2 + (1/2).005*50^2
Would this be right? It seems too simple to me ..
Any help is appreciated.