1. The problem statement, all variables and given/known data A 1500-kg sedan goes through a wide intersection traveling from north to south when it is hit by a 2200-kg SUV traveling from east to west. The two cars become embellished due to the impact and slide as one thereafter. On-the-scene measurements show that the coefficient of kinetic friction between the tires of these cars and the pavement is 0.75, and the cars slide to a halt at a point 5.39 m west and 6.43 m south of the impact point. How fast was each car traveling just before the collision? 2. Relevant equations m1v1+m2v2=MV -->Conservation of momentum Kinematics 3. The attempt at a solution So I started by using the equation μmg=ma and the equation v^2=v^2+2ad to find the velocity of the two cars once they have crashed. It came to 11.108m/s From here I used the conservation of momentum: 1500(Va)+2200(Vb)=(1500+2200)(11.108) 1500Va+2200Vb=41099.6 so then Va=27.4-1.47Vb Because I have two variables I need a second equation so I was trying to use Kinetic Energy. ½ma(Va)^2+½mb(Vb)^2=½MV^2 +Work Done by Friction To find force friction I took the normal force of the two cars stuck together 3700⋅9.8=36260 Friction=μNormal Friction=(0.75)(36260)=27195N Force⋅distance --> 27195(8.39)=228166.1J from here we have 750Va^2+1100Vb^2=210172.2+228166.1 Input Va from the previous expression 750(274.-1.47Vb)^2+1100Vb^2=429238.25 cleaning that up a bit 2720.75Vb^2-60417Vb+133831.75=0 I plugged this into a quadratic equation, but I isn't giving me the correct answer... Any ideas where I went wrong?