Conservation of Momentum in an Explosive Collision

  • Thread starter Thread starter avenkat0
  • Start date Start date
  • Tags Tags
    Momentum Ratio
Click For Summary
SUMMARY

The discussion centers on the application of the conservation of momentum principle in an explosive collision involving a 6.91x106 kg spaceship. The spaceship explodes into two pieces, with one piece having a mass 4.77 times that of the other. The smaller piece moves at 57.6 m/s, leading to an incorrect calculation of the larger piece's speed as -12.075 m/s. The correct approach requires using the momentum equation M1V1 + M2V2 = 0, ensuring that speed is treated as a positive value. Additionally, the discussion highlights the need to correctly apply initial momentum when the spaceship is moving at +18.2 m/s.

PREREQUISITES
  • Understanding of conservation of momentum principles
  • Familiarity with basic physics equations, specifically M1V1 + M2V2 = 0
  • Knowledge of mass and velocity relationships in explosive collisions
  • Ability to perform calculations involving kinetic energy, specifically .5(m)(v2)
NEXT STEPS
  • Review the principles of conservation of momentum in explosive collisions
  • Practice solving problems involving multiple masses and velocities
  • Learn how to calculate kinetic energy from mass and velocity
  • Explore examples of momentum conservation in different reference frames
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and momentum, as well as educators seeking to clarify concepts related to explosive collisions.

avenkat0
Messages
59
Reaction score
0

Homework Statement


A 6.91x106 kg spherical spaceship in deep space explodes into two pieces, one 4.77 times the mass of the other.
a) Suppose the ship is initially at rest, and after the explosion the smaller piece is moving 57.6 m/s.
- Find the speed of the larger piece.
-Find the energy supplied by the explosion.


Homework Equations


M1V1+M2V2=0


The Attempt at a Solution


I tried establishing a ratio of the masses equals the ratio of the velocities and got -12.075 m/s for the larger piece. but got it wrong,
and the second question needs .5(m)(v2) but i don't know the velocity of the heavier mass.
Is there a flaw in my reasoning

Thanks for your help
 
Physics news on Phys.org
avenkat0 said:
I tried establishing a ratio of the masses equals the ratio of the velocities and got -12.075 m/s for the larger piece. but got it wrong,
Looks OK to me, except for the minus sign. (Speed is just a magnitude, thus always positive.)
 
I tried the answer it says its wrong... and then...
c) Suppose the ship is initially moving at constant velocity +18.2 m/s. After the explosion, the smaller piece is moving -57.6 m/s (in the opposite direction to the initial velocity), Find the velocity of the larger piece.

i tried it the same way but with starting momentum 18.2(Mtotal)... and got +9.94... and it says this is wrong as well
is my reasoning flawed? and i double checked my calculations... HELP
 
Last edited:

Similar threads

  • · Replies 4 ·
Replies
4
Views
910
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
5K