1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Velocities and momentum after explosions

  1. Oct 16, 2012 #1
    1. The problem statement, all variables and given/known data
    After several large firecrackers have been inserted into its holes, a bowling ball is projected into the air using a homemade launcher and explodes in midair. During the launch, the 5.43-kg ball is shot into the air with an initial speed of 12.9 m/s at a 39.9° angle; it explodes at a peak of its trajectory, breaking into three pieces of equal mass. One piece travels straight up with a speed of 3.83 m/s. Another piece travels straight back with a speed of 1.71 m/s.

    a) What is the velocity of the third piece?
    Answer calculated: 31.63 m/s

    b) What is the direction of the velocity of the third piece?


    2. Relevant equations
    Momentum is conserved
    m1v1 + m2v2 + m3v3(initial)=m1v1 + m2v2 + m3v3(final)


    3. The attempt at a solution
    I figured since there is no momentum in the y direction at the time of explosion, the y momentum going up must equal the y momentum going down, which is 6.93 kg*m/s.
    With this is took the momentum of the third piece (31.63)(1.81)= 57.25 kg*m/s, then used the tangent inverse tan^-1(-6.93/57.25) to find the angle, but it did not give me the right answer.
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted



Similar Discussions: Velocities and momentum after explosions
  1. Velocity after Impact (Replies: 12)

Loading...