- #1

Priyadarshini

- 191

- 4

## Homework Statement

During an explosion, a bomb explodes into 3 pieces. Two fragments, whose masses are 0.8kg and 0.5kg fly off with velocities of 10m/s and 16m/s respectively along the paths at right angles to each other. If the third fragment goes off with a velocity of 24m/s, then find its mass and direction w.r.t the first fragment.

## Homework Equations

- Components ( u sin A and u cos A)

- Conservation of momentum. The horizontal components=0 and the vertical components=0

## The Attempt at a Solution

For M1

horizontal component of velocity= 10 cos A

vertical component of velocity= 10 sin A

Horizontal momentum= 0.8 x 10cosA

= 8cosA

Vertical momentum=10sinA x 0.8

= 8sinA

For M2

Horizontal component of velocity=16sinA

Vertical Component of velocity= 16cosA

Horizontal momentum= 8sinA

Vertical momentum= 8cosA

How do I find out the direction in which the third pieces moves in? Without the direction on the diagram I've drawn, I cannot split its velocity in component.

Thanks in advance!