1. The problem statement, all variables and given/known data During an explosion, a bomb explodes into 3 pieces. Two fragments, whose masses are 0.8kg and 0.5kg fly off with velocities of 10m/s and 16m/s respectively along the paths at right angles to each other. If the third fragment goes off with a velocity of 24m/s, then find its mass and direction w.r.t the first fragment. 2. Relevant equations - Components ( u sin A and u cos A) - Conservation of momentum. The horizontal components=0 and the vertical components=0 3. The attempt at a solution For M1 horizontal component of velocity= 10 cos A vertical component of velocity= 10 sin A Horizontal momentum= 0.8 x 10cosA = 8cosA Vertical momentum=10sinA x 0.8 = 8sinA For M2 Horizontal component of velocity=16sinA Vertical Component of velocity= 16cosA Horizontal momentum= 8sinA Vertical momentum= 8cosA How do I find out the direction in which the third pieces moves in? Without the direction on the diagram I've drawn, I cannot split its velocity in component. Thanks in advance!