Conservation of momentum in one direction (add or subtract?)

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Homework Help Overview

The discussion revolves around the application of the conservation of momentum in one-dimensional collisions, specifically focusing on when to add or subtract momentum values based on the direction of the objects involved. The original poster presents two scenarios involving collisions between football players and carts, seeking clarification on the correct approach to the momentum equations.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to understand the reasoning behind using addition or subtraction in momentum equations, questioning whether it relates to the direction of the objects' velocities. Some participants suggest using consistent signs for vector directions to clarify the calculations.

Discussion Status

The discussion includes attempts to clarify the original poster's confusion regarding the momentum equations. Some participants provide guidance on maintaining consistent vector signs, while the original poster indicates they have resolved their confusion after a brief absence.

Contextual Notes

The original poster mentions a lack of direct teacher support due to their online course format, which may contribute to their uncertainty about the concepts discussed.

Chris Jarvis
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Homework Statement


Hey everyone! I'm new to these forums so I apologize in advance if I do something wrong! I just had a quick question about the momentum in one direction equation m_1v_1o +/- m_2v_2o = m_1v_1f +/- m_2v_2f; I'm just not sure when I'm supposed to add these values and when I'm supposed to subtract them. I thought it had to do with the objects vector, but there is conflicting questions in my lesson (I think at least). I'm doing an online course so I don't really have a teacher to ask lol
For example:
Football player 1 with a mass of 110kg is moving at 8.0m/s when he crashes into football player 2 with a mass of 105kg, moving at 12 m/s [N]. During the tackle football player 1 holds onto football player 2, giving them the same velocity after 0.30s.
a) Find the final velocity of each player after collision

In a Physics experiment, a 1.2kg cart1 is moving at 3.2m/s [R], when it collides with a 1.8kg cart 2 which is moving at 5.8m/s[L]. After the collision cart1 is moving at 7.6m/s[L].Find the velocity for cart2 after the collision.

Homework Equations


m_1v_1o + m_2v_2o= (m_1+m_2)v_f
m_1v_1o - m_2v_2o = m_1v_1f + m_2v_2f

The Attempt at a Solution


So for the football one my book shows;
Let [N] be positive
P_to=P_tf
m_1v_1o + m_2v_2o= (m_1+m_2)v_f
(110kg)(-8.0m/s)+(105kg)(12m/s)= (110kg +105kg)v_f
v_f=1.77m/s[N]

For the Physics experiment one:
P_1o-P_2o=P_1f+P_2f
Let [R] be positive;
m_1v_1o - m_2v_2o = m_1v_1f + m_2v_2f
(1.2kg)(3.2m/s)-(1.8kg)(5.8m/s)=-(1.2kg)(7.6m/s)+(1.8kg)v_2f
-6.6kgm/s= -9.12kgm/s + (1.8kg)v_2f
v_2f= 1.4m/s [R]
So Is it because the two forces are combining in the first that you add? and in the second one they bounce away so you subtract?
Sorry if this is a really simple question, I haven't done physics in almost 8 years!
Thank you in advance!
 
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Is there a reason most of your text is struck out? Did you still have a question?
 
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Put (+) everywhere and use vector direction to see the correct sign.
 
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Hey sorry everyone I didn't respond I went on vacation and dint have internet but i figured it out thank you both!
 

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