(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A spaceship of mass 2.30×10^6kg is cruising at a speed of 5.40×10^6m/s when the antimatter reactor fails, blowing the ship into three pieces. One section, having a mass of 5.20×10^5kg, is blown straight backward with a speed of 2.20×10^6m/s. A second piece, with mass 7.80×10^5kg, continues forward at 1.20×10^6m/s.

What is the speed of the third piece? in m/s

2. Relevant equations

M3=m3=M-m1+m2

Conservation of Momentum says:

m1v1+m2v2+m3v3=MV

3. The attempt at a solution

To get the weight of the third piece i used

M3=m3=M-m1+m2=

2.30*10^6kg - 5.20*10^5 kg + 7.80*10^5kg= 2.56*10^6 kg

Then

m1v1+m2v2+m3v3=MV

(5.20*10^5kg)(2.20*10^6)+(7.80*10^5kg)(1.20*10^6 m/s)+(2.56*10^6 kg) V3 = (2.30*10^6kg)(5.40*10^6ms)=

This may sound dumb but I don't know how to do this equation

I have 1.44*10^12 + 9.36*10^11 + 2.50*10^6

2.0800025*10^12 = 1.242*10^13

Then do I divide those 2, if so I get 1.67*10^-1 and it's wrong

What am I doing wrong?

Thank you

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# Homework Help: Conservation of Momentum involving a space ship blowing up into three pieces

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