Conservation of Momentum of roller-skates

AI Thread Summary
In the discussion, participants analyze an inelastic collision scenario involving Anthony and Sissy during a roller-skating event. Anthony, weighing 75kg, skates backwards at 3m/s, while Sissy, weighing 60kg, jumps into his arms at 5m/s. The conservation of momentum is applied to calculate their combined velocity after the collision, resulting in a final velocity of approximately 3.9 m/s. The calculation is confirmed as correct, with a note on the importance of rounding. The discussion emphasizes the application of momentum conservation in inelastic collisions.
HeyyMarco
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Homework Statement


Anthony and Sissy are participating in the "Roll-a-Rama" roller-skating dance championship. While 75kg Anthony roller-skates backwards at 3m/s, 60kg Sissy jumps into his arms with a velocity of 5m/s in the same direction.
m1= 75kg
v1= 3m/s
m2= 60kg
v2= 5m/s
v' = ?

Homework Equations



The inelastic collision equation possibly?

The Attempt at a Solution


(75kg)(3m/s) + (60kg)(5m/s)= (75kg+60kg)x
225kg*m/s + 300kg*m/s= 135kg(x)
525kg*m/s = 135kg(x)
(525kg*m/s)/135kg = x
3.8m/s= x

Is that correct?
 
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Yes, it is inelastic collision and your calculation is correct, but take care of rounding. x=3.888... round it to 3.9 m/s.

ehild
 
ehild said:
Yes, it is inelastic collision and your calculation is correct, but take care of rounding. x=3.888... round it to 3.9 m/s.

ehild

Thank you very much :)
 
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