Conservation of Momentum: Understanding the Law and Its Applications

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Homework Help Overview

The discussion revolves around the conservation of momentum, particularly in the context of calculus-based physics. Participants explore when momentum is conserved, the implications of internal and external forces, and the application of impulse-momentum theory.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants question the conditions under which momentum is conserved, specifically in isolated systems. There is discussion about the significance of direction during collisions and the relationship between force, time, and momentum in the context of impulse-momentum theory.

Discussion Status

The conversation is ongoing, with participants sharing insights and clarifications. Some guidance has been offered regarding the integration of equations and the interpretation of momentum in collision scenarios, though no consensus has been reached on specific methods or solutions.

Contextual Notes

Participants express confusion over the application of equations and the formatting of mathematical expressions. There is mention of a specific online platform for physics problems, which may impose certain constraints on the types of questions being discussed.

kyin01
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Homework Statement


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Calculus based so feel free to explain with integrals and such

Homework Equations


[tex]\vec{p}[/tex]=m[tex]\vec{v}[/tex]

Newton's 3rd law, action reaction forces are internal forces.


The Attempt at a Solution


I Guess my question is just understand why I got those answers. I'm a little confused on when momentum is conserved (Law of conservation of momentum). Is it only in an isolated system? Where only internal forces react and external forces equal to 0?

And if that's the case, does that mean law of conservation of momentum states that [tex]\Sigma[/tex][tex]\vec{p}[/tex] = 0 ?

So like for example in question B, why would direction matter? Because either way it still collides right?
 
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Yes that is correct answwer. Its kinda hard to understand at first, but think of the objects moving parellel to x axis, one going positive other in negative way both collide, both didint have same direction, since one direction was negative other was positive . So the correct answer would be dependent on the objects how they were moving previous to collions and sticking
 
Okay, I see what you mean, it can also crash when one is going faster and in the same direction. I just need to get use to it I guess, which brings me to my next problem

Homework Statement


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Homework Equations


[tex]F_{net}[/tex] ([tex]t_{2}[/tex] - [tex]t_{1}[/tex] ) = [tex]mv_{2}[/tex] - [tex]mv_{1}[/tex]
Which is the impluse momentum theory.
I seriously hate the latex coding sometimes, same coding but the right side of the equation didnt make subscripts

The Attempt at a Solution



So I tried integrating the above equation but I don't know how to put it in terms of F and t. I've also tried rearranging the above equation so that momentum at the 2nd time will equal something, but I get a V variable when I did that.
 
Last edited:
well you would be integrating i belivee respect to time from t=0 to some t in the future, btw where are you taking these questions, i kinkda would like to try them myselves :)
 
Hey what program/website/? is that you are using? I really dig that format of how it presents the information and questions.
 
th3plan said:
well you would be integrating i belivee respect to time from t=0 to some t in the future, btw where are you taking these questions, i kinkda would like to try them myselves :)

Yeah that's what I thought too, but when I did that I was left with variables m and t, no F.
And they want it in terms with F

and it's masteringphysics.com
It's a pay site :(
 

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