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Conservation of momentum with unknown angles

  1. Apr 2, 2012 #1
    1. The problem statement, all variables and given/known data
    Ma=2900kg Mb=730kg Va1=11m/s Va2=9m/s Vb1=30m/s Vb2=32.54m/s
    ∅=49.14

    2. Relevant equations
    (2900kg)(49.14)+(730kg)(30m/s*cos(25))=2900kg(9m/s)(cos(α))+730kg(32.54m/s)cos(β)

    and
    (2900kg)(11m/s)+730kg(30m/s*sin(25))=2900kg(9m/s)sin(α)+730kg(32.54m/s)sin(β)


    3. The attempt at a solution
    I have tried substitution by solving for cosα and also by combining the two equations which end up cancelling both coefficients
    1. The problem statement, all variables and given/known data

    I need to solve for both alpha and beta given the two equations

    2. Relevant equations



    3. The attempt at a solution
     
  2. jcsd
  3. Apr 3, 2012 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    Welcome to PF!

    Hi Chrismiss! Welcome to PF! :smile:

    (btw, you don't need to put brackets round those angles, unless your professor tells you to :wink:)

    Let's see … you have

    Acosα + Bcosβ = C

    Asinα + Bsinβ = D​

    … have you tried squaring? :smile:
     
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