Conservation of momentum with unknown angles

[Chrismiss]

Homework Statement

Ma=2900kg Mb=730kg Va1=11m/s Va2=9m/s Vb1=30m/s Vb2=32.54m/s
∅=49.14

Homework Equations

(2900kg)(49.14)+(730kg)(30m/s*cos(25))=2900kg(9m/s)(cos(α))+730kg(32.54m/s)cos(β)

and
(2900kg)(11m/s)+730kg(30m/s*sin(25))=2900kg(9m/s)sin(α)+730kg(32.54m/s)sin(β)

The Attempt at a Solution

I have tried substitution by solving for cosα and also by combining the two equations which end up cancelling both coefficients

Homework Statement

I need to solve for both alpha and beta given the two equations

Homework Equations

The Attempt at a Solution

 

[tiny-tim]

Welcome to PF!

Hi Chrismiss! Welcome to PF!

(btw, you don't need to put brackets round those angles, unless your professor tells you to )

Let's see … you have

Acosα + Bcosβ = C

Asinα + Bsinβ = D​

… have you tried squaring?