Conservation of motion what the velocity of other fragment

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SUMMARY

The discussion focuses on a physics problem involving the conservation of momentum following the explosion of a shell into two equal mass fragments. The initial shell travels horizontally at speed V0, and one fragment moves vertically upward at speed V0. The velocity of the second fragment is determined by applying the momentum conservation principle in both the x and y directions, leading to the conclusion that its velocity is v = (5)^(1/2) V0 at an angle of 26.6 degrees northeast.

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Homework Statement


A shell traveling with speed Vo exactly horizontally and due north explodes into 2 equal mass fragments. One fragment traveling vartically up with speed V0 what is the velocity of the other one?


Homework Equations



v=(m1*v1+m2*v2)/ m1+m2

The Attempt at a Solution


Would I just use this equation and just solve for V2? This is the only formula in the book section that looks like I could use to solve it. But not sure cause this formula is for 2 separate objects that hit each other then moves as a single object, thinking maybe i can make it as a single object that then breaks into 2 objects.
 
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Let the other fragment move at an angle (theta) to the horizontal.
Apply momentum conservation in x and y directions.
Solve 2 equations and you will get your answer
I got v=(5)^1/2 V0 at an angle 26.6 degrees N-E
 
k thxs ill try it out
 

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