Conservation of Momentum of a bomb shell

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Homework Help Overview

The problem involves a shell traveling horizontally that explodes into two equal mass fragments. One fragment moves vertically upward after the explosion, and the task is to determine the velocity of the other fragment. The discussion centers around the conservation of momentum and the vector nature of the problem.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of conservation of momentum in both horizontal and vertical components. There are attempts to clarify the coordinate system being used, with some suggesting that the initial velocity vector should be defined clearly. Others question the validity of different approaches and results obtained by participants.

Discussion Status

There is ongoing exploration of the problem, with various interpretations of the coordinate system and the implications for the solution. Some participants express confusion over the relationship between the components of the velocities, while others provide guidance on using vector notation. A participant has indicated they have derived a specific expression for the velocity of the second fragment but seeks validation of that result.

Contextual Notes

Participants have noted the importance of defining the coordinate system clearly, as differing interpretations may lead to confusion. There is also mention of the problem being two-dimensional, which affects how the components of the velocities are analyzed.

  • #31
heycoa said:
p0=2m*v0
p1=m*v0
Don't forget they have directions associated with them.

Now, find p2 ?
 
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  • #32
so the direction of p0 is in the x-direction, and p1 is in the y-direction?
 
  • #33
heycoa said:
so the direction of p0 is in the x-direction, and p1 is in the y-direction?
Yes ...
 
  • #34
well p2=v2*m

and when i solve for v2 i get 2*v0(x hat) + v0(y hat)
 
  • #35
heycoa said:
well p2=v2*m

and when i solve for v2 i get 2*v0(x hat) + v0(y hat)

From that I get ##\ \vec{p_2}=2\,m\,v_0\hat{x}+m\,v_0\hat{y}\ . ##

Adding p1 and p2 should give p0, right?
 
  • #36
Then it should be minus the second term (-m*v0*yhat), right?
 
  • #37
heycoa said:
Then it should be minus the second term (-m*v0*yhat), right?
Yes, for p2.

What does this give you for the vector, v2, and its direction, and its magnitude, v2 ?
 
  • #38
for v2 i get 2*v0(x hat) + v0(y hat)

i calculated the magnitude to be v2=v0*sqrt(5)

does this appear to be correct?
 
  • #39
heycoa said:
for v2 i get 2*v0(x hat) + v0(y hat)

i calculated the magnitude to be v2=v0*sqrt(5)

does this appear to be correct?
Yes !
 
  • #40
Ok excellent!

So I apparently need to read these questions more carefully and define my coordinate systems.

I can't thank you enough for taking the time and having the patience to work with and follow up with me. Thank you very much
 
  • #41
heycoa said:
Ok excellent!

So I apparently need to read these questions more carefully and define my coordinate systems.

I can't thank you enough for taking the time and having the patience to work with and follow up with me. Thank you very much
You're welcome.

I hope I wasn't being too difficult at times.
 
  • #42
no you're great! :)
 

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