Consider the arrangement of two fixed point charges, equal in magnitude

In summary, the correct statements for the initial motion of a third charge released in the vicinity of two fixed point charges, equal in magnitude, are: a negative charge at point e will accelerate up, a negative charge at point b will accelerate down, and a positive charge at point a will accelerate toward the lower-left. The incorrect statement is that a negative charge at point c will accelerate toward the lower-right. This is because the direction of the electric field at point c is tangential to the field line, which does not necessarily mean it will accelerate in that direction. The acceleration vector would be a combination of the electric field vectors at that point.
  • #1
Physics1988
2
0
Consider the arrangement of two fixed point charges, equal in magnitude...

Consider the arrangement of two fixed point charges, equal in magnitude, shown in the figure.
Which of the following statements are correct for the initial motion of a third charge if it is released from rest in the vicinity of the two charges shown?
IMAGE: http://i51.tinypic.com/2akeovn.gif

A negative charge at point d will accelerate down. (false)
A negative charge at point e will accelerate up. (true)
A negative charge at point b will accelerate down.(true)
A positive charge at point a will accelerate toward the lower-left. (false)
A negative charge at point c will accelerate toward the lower-right. (true)

I have no idea why this is wrong. I thought it would be an easy, 30 second question but I just can't seem to get it. The answers to the left is what I think is right, but is apparently wrong.

PLEASE, an explanation!

Ok so this is my thought process. A negative charge at D will be repulsed by the negatively charged point. A negative charge at e will be attracted to the positively charged point. B will be both attracted to the positive point and repulsed by the negative. If I draw vectors, the vector sum of A is on the top left and for C, it is on the lower right.Just realized that this might be in the wrong section. Sorry, first time posting. Please feel free to move.
 
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  • #2


Welcome to PF, 1988.

I would say the answers are correct except for the last question, the negative charge at c. If you draw the force vectors on c, one away from the negative charge and the other toward the positive charge, you will see that the horizontal parts cancel out and the total force is straight down.
 
  • #3


Thank you for the welcome!

And yes you are correct, that was the one that was wrong.

I thought they meant that it ends up somewhere in the lower-right, which is why I said it was true. Turns out they are asking if the DIRECTION is lower-right, which it is not.

I also found this :
http://tinypic.com/r/fxs4yo/7

So I guess any point would have to be in the positive-to-negative trajectory?
 
  • #4


Yes, the direction is the thing. The fxs4yo/7 link is to an electric field line diagram, not the same thing as a vector direction. The direction of the electric field at any point would be tangential to the field line at that point.

So I guess any point would have to be in the positive-to-negative trajectory?
I don't follow this terminology . . . trajectory means "flight path" to me. Here the velocity vector would be tangential to the trajectory. I can't quite picture how the acceleration vector would be related.
 
  • #5


No worries, we can still provide an explanation for you. Let's break down each statement and see why it is correct or incorrect.

1. A negative charge at point d will accelerate down. (false)
This statement is false because a negative charge will be repelled by the negative charge at point A, causing it to accelerate away from it, not towards it.

2. A negative charge at point e will accelerate up. (true)
This statement is true because a negative charge will be attracted to the positive charge at point B, causing it to accelerate towards it.

3. A negative charge at point b will accelerate down. (true)
This statement is true because a negative charge will be repelled by the negative charge at point A and attracted to the positive charge at point B, causing it to accelerate downwards.

4. A positive charge at point a will accelerate toward the lower-left. (false)
This statement is false because a positive charge will be attracted to the negative charge at point A, causing it to accelerate towards it, not away from it.

5. A negative charge at point c will accelerate toward the lower-right. (true)
This statement is true because a negative charge will be repelled by the negative charge at point A and attracted to the positive charge at point B, causing it to accelerate towards the lower-right direction.

Overall, the key concept to keep in mind is that like charges repel each other and opposite charges attract each other, causing the third charge to move in a certain direction based on the arrangement of the two fixed charges. I hope this explanation helps!
 

1. What is the formula for calculating the electric potential energy between two fixed point charges?

The formula for calculating the electric potential energy between two fixed point charges is U = k * (q1 * q2)/r, where U is the potential energy, k is the Coulomb's constant, q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.

2. How does the distance between two fixed point charges affect the electric potential energy?

The electric potential energy between two fixed point charges is inversely proportional to the distance between the charges. This means that as the distance between the charges increases, the potential energy decreases, and as the distance decreases, the potential energy increases.

3. Can the electric potential energy between two fixed point charges ever be negative?

Yes, the electric potential energy between two fixed point charges can be negative. This occurs when the two charges have opposite signs and are attracted to each other.

4. What happens to the electric potential energy between two fixed point charges if one of the charges is doubled?

If one of the charges is doubled, the electric potential energy between the two charges will also double. This is because the potential energy is directly proportional to the magnitude of the charges.

5. How does the electric potential energy between two fixed point charges change if the charges are brought closer together?

If the charges are brought closer together, the electric potential energy between them will increase. This is because the potential energy is inversely proportional to the distance between the charges. As the distance decreases, the potential energy increases.

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