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tAzneem

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An antelope moving with constant acceleration covers the distance 80.0m between

two points in time 6.70s. Its speed as it passes the second point is 14.6 m/s.

1) What is its speed at the first point?

2) What is the acceleration?

First I understand that when we have (constant acceleration) that means --> Vo=0m/s

*_______________* If that was the two points , so t1=0 , t2=6.70 and the all distance is 80

Vx=14.6

For 1 ) I though the answer will be zero OR can we do 80/6.70=11.9 , I really have an issue to know if the speed they are talking about is v=Δx/t or they are talking about S=D/t

2) α= Δv/Δt --> 14.6/6.70 = 2.2m/s^2