Constant Motion Vs. Acceleration

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SUMMARY

The discussion centers on a physics problem involving a motorcyclist traveling at a constant speed of 15 m/s and a police officer accelerating from rest at 3 m/s². The key equations used include V(bar) = d/t and a = ΔV/t. The police officer's displacement is modeled using the equations of motion for constant acceleration, leading to the conclusion that the time taken for the police to catch the motorcyclist is 18.75 seconds, with a total displacement of 140.625 meters. The final speed of the police car at the moment of catching up was not explicitly calculated in the discussion.

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  • Knowledge of velocity and displacement relationships
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jessicayin22
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Homework Statement


A reckless motorcyclist drives past a school zone at a constant speed of 15 m/s , where the speed limit is only 10 m/s. at the same moment a police officer chases the motorcyclist from rest and accelerating at the rate of 3 m/s?
a. how fardoes the police travel before catching up to the motorcyclist?
b. how much time does it take the police car to catch up to the motorcyclist?
c. how fast is the police car traveling when it catches the motorcyclist?

Homework Equations


V(bar)=d/t, a= deltaV/t,

The Attempt at a Solution


okay, so i know that displacement is equal to each other, I've set the equations equal to each other and then solved for t...??
 
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jessicayin22 said:

Homework Statement


A reckless motorcyclist drives past a school zone at a constant speed of 15 m/s , where the speed limit is only 10 m/s. at the same moment a police officer chases the motorcyclist from rest and accelerating at the rate of 3 m/s?

Homework Equations


V(bar)=d/t, a= deltaV/t,


The Attempt at a Solution


do not know how to start...

You have a question mark, but have not actually asked a question.

I assume you want to know when the policeman catches the motorcyclist.

You could draw/sketch velocity time graphs of the situation and instantly see the answer.

Displacement of the reckless one is 15t

Displacement of the policeman follows "the equations of motion with constant acceleration" and one of them is really appropriate.

The displacements will of course be equal.
 
i set the equation and found out T= 18.75? ... but it doesn't make sense since the displacement eauals 140.625m
 

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