Constant velocity on frictional slope

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Homework Help Overview

The discussion revolves around the dynamics of a sphere rolling down a frictional slope while maintaining a constant velocity. Participants explore the relationship between gravitational and frictional forces and their effects on the motion of the sphere, particularly in the context of rolling without slipping.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss various approaches to derive the acceleration of the sphere using torque and energy relations. There are attempts to reconcile different expressions for acceleration and questions about the role of friction in the rolling motion.

Discussion Status

The discussion is active, with participants sharing their derivations and questioning discrepancies in their results. Some guidance is offered regarding the role of friction and energy conservation, but multiple interpretations of the problem are being explored.

Contextual Notes

Participants note that the problem may not be a formal homework question, and there are discussions about the assumptions regarding rolling without slipping and the effects of friction on the motion.

Loren Booda
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Derive the slope of a track where a sphere having frictional coefficient u maintains constant velocity v.
 
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Show us what you've tried so far.
 
Tide,

It's not a homework problem (yet?), but I appreciate your response. I thought someone might have fun working out this nontrivial, simply stated puzzle.
 
If I use Torque = I * alpha and Newtons second law, I end up with the following for acceleration.

a = mg sin(theta) * r^2 /(I + mr^2) where I is w.r.t. the center of the rolling object.


If I use the energy relation (i.e Change in Energy = work done by the force), I get

a = g[2 sin (theta) + u cos(theta)] / ( 1 + I/mr^2)

I can't figure out where the discripancy is.
 
Gamma said:
If I use Torque = I * alpha and Newtons second law, I end up with the following for acceleration.

a = mg sin(theta) * r^2 /(I + mr^2) where I is w.r.t. the center of the rolling object.
Assuming the sphere rolls without slipping, this looks good.


If I use the energy relation (i.e Change in Energy = work done by the force), I get

a = g[2 sin (theta) + u cos(theta)] / ( 1 + I/mr^2)
Not sure what you did here. Realize that as long as the sphere rolls without slipping, the friction does no work.
 
Say that the sphere rolls down from top a distance x.

Final Energy Ef= 1/2 I w^2 + 1/2 m v^2 - mgx sin(theta). Of course if the energy is conserved I can show that accelaration 'a' is same as the first expression in my post which is correct for a rolling object down the hill.

So my question is what effect do the gravitational and frictional forces have on the rolling motion? What makes the ball roll?
 
Last edited:
If there were no friction, the ball would slide down the hill without rolling. Friction exerts the torque (about the ball's center of mass) that makes the ball rotate as well as translate. As long as the friction is sufficient to make the ball roll without slipping, the friction does no work and mechanical energy is conserved. Friction enables the gravitational PE to be transformed into both rotational and translational KE.
 
Last edited:

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