Constrained Motion Problem: Understanding the First Step in the Solution

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Homework Help Overview

The discussion revolves around a constrained motion problem involving the application of Pythagoras' theorem and its time derivative. The original poster expresses confusion regarding the first step in a provided solution, which involves an equation relating two variables, Xa and Xb, to a constant length L.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the reasoning behind the application of Pythagoras' theorem and the subsequent time derivative. Questions arise about the interpretation of the derivative and the use of the chain rule.

Discussion Status

Some participants have offered clarifications regarding the application of mathematical principles, while others are still questioning the assumptions and steps involved. There appears to be a mix of understanding and confusion among participants, with some expressing clarity after further discussion.

Contextual Notes

There is a reference to a picture that is not included in the thread, which may contain relevant information for understanding the problem setup. Additionally, the discussion hints at the use of specific homework rules regarding the presentation of solutions.

Clever_name
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Homework Statement



See attached picture.

Homework Equations


The Attempt at a Solution



I have the solution, but I'm puzzled by the first step in their solution, which reads

Xa^(2) + Xb^(2) = L^(2)

The solution provider then takes the time derivative of this expression which then produces

2Xa(Xa(dot))+2Xb(Xb(dot)) = 0

where Xa(dot) and Xb(dot) is the Xa or Xb symbol with a dot over it.

Thanks for you're assistance!
 

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Here is the solution if my explanation was confusing in any way.
 

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Any help would be greatly appreciated.
 
I don't understand what's puzzling you. The first line is just Pythagoras' theorem applied to the triangle of which AB is the hypotenuse.
 
The line below it, when taking the time derivative of the first line how do they end up with that expression?
 
If x = x(t), can you write down the expression for (d/dt)x2?
 
2x? or x(t)dx/dt = x(t)*x'(t)
 
How did you know that x was a function of time?
 
Clever_name said:
2x? or x(t)dx/dt = x(t)*x'(t)
No, but each answer you offer is half right. Do you know the chain rule?
 
  • #10
yep, i understand now haruspex, thanks!
 

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