Constructing a Normal Series for G from Given Normal Series for N and G/N

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SUMMARY

The discussion focuses on constructing a normal series U for a group G, given normal series S for a normal subgroup N and T for the quotient group G/N. The solution involves using the correspondence theorem to map the normal series T to a normal series from N to G. The key conclusion is that two normal series are isomorphic if there exists a bijection between their factors such that corresponding factors are isomorphic, which aligns with the definition of equivalence in group theory.

PREREQUISITES
  • Understanding of normal subgroups in group theory
  • Familiarity with normal series and their properties
  • Knowledge of the correspondence theorem in abstract algebra
  • Concept of isomorphism and equivalence of mathematical structures
NEXT STEPS
  • Study the Jordan-Hölder theorem and its implications in group theory
  • Learn about the correspondence theorem in detail
  • Explore examples of constructing normal series from given normal subgroups
  • Investigate the concept of isomorphism in the context of group factors
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Undergraduate students in Abstract Algebra, educators teaching group theory concepts, and mathematicians interested in the structure of groups and normal series.

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Homework Statement



Suppose that N \triangleleft G. Show that given normal series S for N and T for G / N one can construct a normal series U for G such that the first part of U is isomorphic to S and the rest is isomorphic to T.


Homework Equations



This is from the last couple of weeks of an undergraduate Abstract Algebra course. The teacher assigned it as homework while discussing a proof of the Jordan-Holder theorem.

The Attempt at a Solution



I'd like to simply construct U from S and T. Using S would be straightforward as this is already a normal series from \left\{ e \right\} to N. However, I'd hoped to use correspondence theorem to map the normal series T to a normal series from N to G. I believe, however that there is a problem with the part where it says this part of the series should be isomorphic to T.
 
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What does it mean to say that two normal series are isomorphic?
 
I guess that was the part I was confused about as well. My roommate now informs me that we defined two normal series to be isomorphic as follows:

Series S and T are isomorphic if there exists a bijection from the factors of S to the factors of T such that the corresponding factors are isomorphic.

So, that makes a bit more sense to me now.
 
Typically that's referred to as "equivalence", but anyway, your idea does work, i.e. it will produce an equivalent normal series.
 

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