[tex]y=\sqrt{x+\sqrt{x+\sqrt{x+...}}}[/tex]
From your observation
[tex]y^2-y-x=0[/tex]
[tex]y=\frac{1}{2}(1 \pm \sqrt{1+4x})[/tex]
as x>0,y>0
[tex]y=\frac{1}{2}(1+\sqrt{1+4x})[/tex]
But from the first formula, y(x=0) should be zero. How can we get value of y(x=1) from it which does not show us initial value ? I am afraid this formula is not defined well enough.