- #1

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I am not sure what this function actually is... is it a mapping from M -> M or some other mapping? Is the image of the function in M? Any help would be greatly appreciated!

- Thread starter roman93
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- #1

- 14

- 0

I am not sure what this function actually is... is it a mapping from M -> M or some other mapping? Is the image of the function in M? Any help would be greatly appreciated!

- #2

Stephen Tashi

Science Advisor

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I suggest that you explain where you saw this statement and quote it exactly.is it a mapping from M -> M or some other mapping?

- #3

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This is what I would call bounded. But you will need to specify the context.

- #4

HallsofIvy

Science Advisor

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Since f(p)= p is continuous, one thing that tells you is that M itself is bounded!

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