Continuous Grey Atmosphere Model

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SUMMARY

The discussion focuses on the Continuous Grey Atmosphere Model, specifically applied to Venus's atmospheric conditions. Participants analyze the total optical thickness using the grey atmosphere model and derive the temperature difference between ground temperature (Tg) and atmospheric temperature at ground level. Key equations include the relationship between ground and emission temperatures, represented as T_g^4 = T_e^4(1 + (3/4)τ) and τ = (T_g^4/T_e^4) - 1. The conversation emphasizes the importance of correctly applying these equations to solve the homework problems.

PREREQUISITES
  • Understanding of radiative energy balance in atmospheric models
  • Familiarity with optical depth concepts in atmospheric science
  • Knowledge of thermodynamic temperature relationships
  • Proficiency in algebraic manipulation of equations
NEXT STEPS
  • Research the derivation of optical depth equations in atmospheric models
  • Study the implications of temperature variations in grey atmosphere models
  • Explore the application of the Stefan-Boltzmann law in radiative transfer
  • Learn about the impact of atmospheric composition on radiative balance
USEFUL FOR

This discussion is beneficial for students and researchers in atmospheric sciences, particularly those studying radiative transfer and energy balance in planetary atmospheres.

il27

Homework Statement


In the grey atmosphere radiative energy balance model, we replace the multi-layer approximation used above with still simplified but significantly more realistic model involving a continuous atmosphere with a continuously varying temperature. The variation with temperature is a function of optical depth.

a) Find the total optical thickness of the atmosphere of Venus using the gray atmosphere model. Assume the same emission and ground temperatures as in the previous question.

b) Find the temperature difference between the ground temperature Tg and the atmospheric temperature at ground level.

Homework Equations



$$ T_g ^4 = T_e ^4(1 + \frac{3}{4} \tau) $$

There is another equation for optical depth, but I am not sure how to derive this:

$$ \tau = \frac{T_g ^4}{T_e ^4} - 1 $$

$$ T_e = (\frac{(1-\alpha)}{4 \sigma} F_0)^.25 $$

The Attempt at a Solution



I am thinking I can calculate the emission temperature with the 3rd equation, but I am stuck on finding the ground temperature.
Also which optical depth equation is correct?
 
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