Continuous periodic piecewise differentiable

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SUMMARY

The discussion centers on proving that for a continuous periodic piecewise differentiable function \( f(\theta) \), the equation \( f(\theta) = f(0) + \int_0^{\theta}g(t)dt \) holds true, where \( g \) is piecewise continuous. The proof hinges on the differentiability of \( f \) at most points, leveraging the finite number of non-differentiable points to establish the relationship. This conclusion is critical for understanding the behavior of such functions in mathematical analysis.

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  • Understanding of continuous functions and periodicity
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  • Basic concepts of piecewise continuous functions
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Dustinsfl
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Suppose that $f(\theta)$ is a continuous periodic piecewise differentiable function. Prove that $f(\theta) = f(0) + \int_0^{\theta}g(t)dt$ for a piecewise continuous $g$.

I just need a nudge in the right direction here.
 
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Can you do it when $f$ is differentiable? THen use the fact that there are only finite many points where $f$ is not differentiable.
 

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