Continuous random variable question

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The discussion focuses on calculating probabilities and the mean of a continuous random variable defined by the probability function f(X)=(X+1)/8 for -1<=X<=3. The probability Pr(X<=2) can be determined by finding the area under the density function from -1 to 2. The mean of X is correctly calculated as 5/3 using the integral ∫ x * f(x) dx over the specified interval, yielding the expected value of the random variable.

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A continuous random variable x has the following probability function:
f(X)=(X+1)/8
-1<=X<=3
0 Otherwise

1. Find the Pr(X<=2)
2. Find the mean of X
 
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Hello and welcome to MHB! :D

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mean of X is defined as ∫ x * f (x) dx over the domain of definition of X
∫ x (x + 1) / 8 dx
= ∫ (x^2 + x) / 8 dx
= x^3 / 24 + x^2 / 16 + c
Over the interval [-1, 3], we get:
(3^3 - (-1)^3) / 24 + (3^2 - (-1)^2) / 16
= 7/6 + 1/2
= 5/3

Im I right?
 
Last edited:
Your calculation of the expected value (=mean) is correct. Have you already figured out how to compute $\mathbb{P}(X \leq 2)$?

Hint: use the link between a probability and the area under a density function
 

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