Contracting Loop in a Magnetic Field

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Homework Help Overview

The problem involves an elastic circular loop in a magnetic field, specifically examining how changes in the loop's diameter affect the induced electromotive force (emf) and current. The magnetic field strength is given, and the loop's diameter changes over a specified time period.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of magnetic flux and the importance of determining the change in area rather than diameter. There are attempts to clarify the correct method for calculating the change in flux and its impact on the induced emf.

Discussion Status

Multiple interpretations of the problem are being explored, particularly regarding the calculation of area and flux. Some participants have provided guidance on correcting the approach, while others continue to express uncertainty about the results obtained.

Contextual Notes

Participants note the need to consider the definition of "magnitude" in the context of the problem, indicating a potential misunderstanding in the interpretation of results. There is also mention of specific values and calculations that have been attempted, but no consensus on the correctness of the final answers has been reached.

Angie K.
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Homework Statement



An elastic circular loop in the plane of the paper lies in a 0.81 T magnetic field pointing into the paper. If the loop's diameter changes from 19 cm to 6.8 cm in 0.45 s,

a. what is the magnitude of the average induced emf?

b. If the loop's resistance is 2.3 Ω, what is the average induced current I during the 0.45 s?

Homework Equations



emf = change in flux * B / change in time

magnetic flux = B*A cos Theta

The Attempt at a Solution



Using the equation from above,

the distance that I am going to use is .19m - .068m = .122 m (change in distance)

magnetic flux = (0.81T)(pi)(0.122m)^2 cos 0

= 3.7875*10^-2 T/m^2

emf = (3.7875*10^-2 T/m^2) / 0.45s = 8.4167*10^-2 Volts

Which is wrong but I am not sure where I went wrong.
Maybe something with the distance? Because I feel like that's the one place where I could have messed up...

Thanks in advance!
 
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You made a mistake here:
Angie K. said:
the distance that I am going to use is .19m - .068m = .122 m (change in distance)

magnetic flux = (0.81T)(pi)(0.122m)^2 cos 0

You need to calculate the change in area, not the change in diameter.
You want this: ## \Delta A = A_{final}-A_{initial} = \pi r_{final}^2-\pi r]_{initial}^2 ##
Try that and see if it works.
 
Last edited:
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Angie K. said:
the distance that I am going to use is .19m - .068m = .122 m (change in distance)

magnetic flux = (0.81T)(pi)(0.122m)^2 cos 0

This is where the mistake is. Try finding the initial total flux and then the final total flux (after 0.45 s). Use these to get the change in flux.

[You can ignore my post. BiGyElLoWhAt already posted]
 
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Beat you ;)
 
BiGyElLoWhAt said:
Beat you ;)
:H
 
BiGyElLoWhAt said:
You made a mistake here:You need to calculate the change in area, not the change in diameter.
You want this: ## \Delta A = A_{final}-A_{initial} = \pi r_{final}^2-\pi r]_{initial}^2 ##
Try that and see if it works.

BiGyElLoWhAt said:
Beat you ;)

For initial flux : .81T (pi*r (.19^2) = 9.18633e-2
For final flux: .81T (pi*r (.068^2) = 1.17666e-2

so the change in flux is 1.17666e-2 - 9.18633e-2 = - .0800967

so I plug that into find Emf:

magnitude of emf (- .0800967/0.45s) and it still isn't the right answer.
 
Angie K. said:
For initial flux : .81T (pi*r (.19^2) = 9.18633e-2
For final flux: .81T (pi*r (.068^2) = 1.17666e-2

so the change in flux is 1.17666e-2 - 9.18633e-2 = - .0800967

so I plug that into find Emf:

magnitude of emf (- .0800967/0.45s) and it still isn't the right answer.
Looks good except you need to interpret the word "magnitude".
 
TSny said:
Looks good except you need to interpret the word "magnitude".

BiGyElLoWhAt said:
Beat you ;)

I got the right answer for both parts. Thanks to you both for the help!
 

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