Contraction and contractive mapping

  • Context: MHB 
  • Thread starter Thread starter ozkan12
  • Start date Start date
  • Tags Tags
    Contraction Mapping
Click For Summary

Discussion Overview

The discussion revolves around the concept of contraction mappings within the context of complete metric spaces. Participants explore the implications of a specific condition on a function \( f: X \to X \) and its relation to the definition of contraction mappings, seeking clarification on how these concepts interrelate.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant presents a condition involving \( f \) and asks for help understanding how this relates to contraction mappings.
  • Another participant provides the formal definition of a contraction mapping and suggests that the initial condition needs to be reformulated to match this definition.
  • A different participant reiterates the condition and attempts to frame it as a theorem, indicating a perceived connection to contraction mappings but expressing confusion.
  • Further clarification is sought regarding the precise statement of the condition and its implications for \( f \) being a contraction mapping.
  • One participant insists on the specific condition involving \( \epsilon \) and \( \delta \) and questions how this leads to the concept of contraction mappings.

Areas of Agreement / Disagreement

Participants express uncertainty about the clarity and implications of the condition related to contraction mappings. There is no consensus on how to interpret the condition or its relationship to the definition of contraction mappings.

Contextual Notes

The discussion highlights potential ambiguities in the formulation of the condition and its dependence on the definitions used. Participants have not resolved the mathematical steps needed to connect the condition to the standard definition of contraction mappings.

ozkan12
Messages
145
Reaction score
0
Let $(X,d)$ be a complete metric space, and suppose that $f:X \to X$ satisfies the condition: for each $\epsilon >0$, there exists $\delta > 0$ such that for all $x,y \in X$

$$ \epsilon \le d(x,y) < \epsilon+\delta \implies d(f(x),f(y)) < \epsilon.$$Clearly, this condition implies that the mapping $f$ is contractive... also $f$ map is contraction...but I don't understand ? how this contraction, how this happened ? please help me :) thanks a lot :)
 
Last edited by a moderator:
Physics news on Phys.org
Here's the definition of a contraction mapping on a metric space:

A function $f:M \to M$ is a contraction mapping iff there exists a real number $k\in [0,1)$ such that for all $x,y \in M$, we have $d(f(x),f(y)) \le k \, d(x,y)$.

It seems to me that we need to massage the condition you were given to look like the definition of a contraction mapping. How do you think we could do that?
 
Let $(X,d)$ be a complete metric space, and suppose that $f:X\to X$ satisfies the condition: for each $\epsilon >0$, there exists $\delta > 0$ such that for all $x,y \in X$,

$$\epsilon \le d(x,y) \implies d(f(x),f(y)) < \epsilon.$$this write in theorem...and this case has a relation with contraction mapping but I don't understand...I wrote this as in the theorem
 
Last edited by a moderator:
ozkan12 said:
Let (X,d) be a complete metric space, and suppose that f:X>>>>X satisfies the condition: for each epsilon >0, there exists delta > 0 such that for all x,y in X

epsilon <=d(x,y) d(f(x),f(y))< epsilonthis write in theorem...and this case has a relation with contraction mapping but I don't understand...I wrote this as in the theorem

Hi ozkan12,

It's not clear what the statement is. Are supposing that $f : X \to X$ satisfies the property that for every $\epsilon$, there is a $\delta > 0$ such that for all $x,y \in X$, $d(x,y) \ge \mathbf{\delta}$ implies $d(f(x),f(y)) < \epsilon$?
 
no, $f$ satisfies this condition

$$\epsilon \le d(x,y) <\epsilon+\delta \implies d(f(x),f(y))< \epsilon$$

then this concept has a relation contraction map...but it how happen ? I don't understand
 
Last edited by a moderator:

Similar threads

  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
1K
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K