Contravariant Four-gradient ESN in Wikipedia appears wrong

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The discussion focuses on the perceived inaccuracies in the contravariant four-gradient representation on Wikipedia. Participants express concern over the presence of negative signs in the initial lines of the equation, suggesting they may be incorrect. They agree that the Einstein summation notation should not include these negatives and provide an alternative formulation for clarity. The conversation emphasizes the importance of correctly representing the four-gradient in the context of relativity. Overall, the participants seek to clarify and correct the Wikipedia entry for better accuracy.
SpecialEd
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Homework Statement


I am self studying relativity. In Wikipedia under the four-gradient section, the contravariant four-vector looks wrong from an Einstein summation notation point of view.

https://en.wikipedia.org/wiki/Four-vector

Homework Equations



It states:

E
00-E11-E22-E33 = Eαα

The Attempt at a Solution


As it is it looks wrong to me. Is it wrong or is it NOT ESN or something else?
 
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Welcome to PF!
I agree with you that it doesn't look right. For the contravariant form of the 4-gradient they have
upload_2016-10-11_22-11-0.png

I don't think there should be any negative signs in the first four lines. The last four lines look correct to me. So, I believe the Einstein summation works as follows $$\partial = E_\alpha \partial^\alpha = E_0 \partial ^0 + E_1 \partial ^1 +E_2 \partial ^2 + E_3 \partial ^3$$ where $$\partial^1 \equiv \frac{\partial}{\partial x_ {_1}} = -\frac{\partial}{\partial x^1}$$ etc.
 
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TSny said:
Welcome to PF!
I agree with you that it doesn't look right. For the contravariant form of the 4-gradient they have
View attachment 107315
I don't think there should be any negative signs in the first four lines. The last four lines look correct to me. So, I believe the Einstein summation works as follows $$\partial = E_\alpha \partial^\alpha = E_0 \partial ^0 + E_1 \partial ^1 +E_2 \partial ^2 + E_3 \partial ^3$$ where $$\partial^1 \equiv \frac{\partial}{\partial x_ {_1}} = -\frac{\partial}{\partial x^1}$$ etc.

Thanks so much for your comment and help!
 

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