Bazzinga
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So I have this series:
\sum^{infinity}_{n=3}(-1)^{n-1}\frac{ln(n)}{n}
And I'm trying to use the AST to find out if it converges or not.
First of all, I'm stuck trying to show that ln(n)/n is decreasing...
But then after that. I'm assuming I can compare it with 1/n to show that it diverges absolutely, but converges conditionally (since the limit as n -> infinity of ln(n)/n is 0)
I was just wondering what converging absolutely and conditionally meant? We learned in class that absolute convergence implies convergence, does this mean that if its only conditionally convergent it doesn't converge?
\sum^{infinity}_{n=3}(-1)^{n-1}\frac{ln(n)}{n}
And I'm trying to use the AST to find out if it converges or not.
First of all, I'm stuck trying to show that ln(n)/n is decreasing...
But then after that. I'm assuming I can compare it with 1/n to show that it diverges absolutely, but converges conditionally (since the limit as n -> infinity of ln(n)/n is 0)
I was just wondering what converging absolutely and conditionally meant? We learned in class that absolute convergence implies convergence, does this mean that if its only conditionally convergent it doesn't converge?