Convergence and Comparison: Analyzing the Alternating Series Test

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SUMMARY

The discussion centers on the Alternating Series Test (AST) applied to the series \(\sum^{\infty}_{n=3}(-1)^{n-1}\frac{\ln(n)}{n}\). The user seeks to demonstrate that \(\frac{\ln(n)}{n}\) is decreasing and compares it to \(\frac{1}{n}\) to establish that the series diverges absolutely but converges conditionally. The conversation clarifies that absolute convergence implies convergence, while conditional convergence does not guarantee absolute convergence, highlighting the importance of distinguishing between the two types for advanced mathematical applications.

PREREQUISITES
  • Understanding of the Alternating Series Test (AST)
  • Knowledge of convergence concepts: absolute and conditional convergence
  • Familiarity with derivatives and their role in determining monotonicity
  • Basic calculus, particularly limits and series
NEXT STEPS
  • Study the properties of absolute convergence versus conditional convergence
  • Learn how to apply the Alternating Series Test in various scenarios
  • Explore examples of conditionally convergent series, such as \(\sum\frac{(-1)^n}{n}\)
  • Investigate the implications of rearranging terms in conditionally convergent series
USEFUL FOR

Mathematics students, educators, and anyone interested in series convergence, particularly those studying calculus or advanced mathematical analysis.

Bazzinga
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So I have this series:

\sum^{infinity}_{n=3}(-1)^{n-1}\frac{ln(n)}{n}

And I'm trying to use the AST to find out if it converges or not.
First of all, I'm stuck trying to show that ln(n)/n is decreasing...

But then after that. I'm assuming I can compare it with 1/n to show that it diverges absolutely, but converges conditionally (since the limit as n -> infinity of ln(n)/n is 0)

I was just wondering what converging absolutely and conditionally meant? We learned in class that absolute convergence implies convergence, does this mean that if its only conditionally convergent it doesn't converge?
 
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Bazzinga said:
So I have this series:

\sum^{infinity}_{n=3}(-1)^{n-1}\frac{ln(n)}{n}

And I'm trying to use the AST to find out if it converges or not.
First of all, I'm stuck trying to show that ln(n)/n is decreasing...

Consider the continuous extension of this function, i.e. consider the function

f:]0,+\infty[\rightarrow \mathbb{R}:x\rightarrow \frac{ln(x)}{x}

it suffices to show that this function is decreasing (from a certain point on). To show this, it suffices to calculate the derivative of the function and seeing where it is negative.

But then after that. I'm assuming I can compare it with 1/n to show that it diverges absolutely, but converges conditionally (since the limit as n -> infinity of ln(n)/n is 0)

I was just wondering what converging absolutely and conditionally meant? We learned in class that absolute convergence implies convergence, does this mean that if its only conditionally convergent it doesn't converge?

Well, absolute convergence happens when the series of absolute values converge. Absolute convergence is stronger then convergence. However, there are series which converge and do not converge absolutely. This type of convergence is conditionally convergence.An example of this phenomenon is

\sum\frac{(-1}^n}{n}

So series can do three kind of things: they can diverge, they can converge absolutely and they can converge conditionally.
 
Ok, I understand that, but what's the difference between conditional convergence and absolute convergence? I always thought it was just 1s and 0s, it either converges or not, but conditional convergence is in between? Does is converge slower or something?
 
No, there is nothing slower about conditional convergence (that I know of). Both conditional and absolute convergence is convergence. The only difference is that conditional convergent series do not converge absolute, while absolutely convergent sequences do.

The reason that mathematicians make the distinction is because there are a lot of nice properties of absolute convergent series that conditional convergent series do not have. For instance, in an absolute convergent series, you can put all the summands in an other place, and the series will still converge. Thus the convergence is commutative. However, a conditional convegent series is not commutative. There are some other distinctions, but you'll see them soon I guess...

If you're just interested in convergence of series, then there is no need for a distinction between conditional and absolute. However, if you want to do tricky things with the series, then such a distinction is necessairy!
 
Ohh that's interesting! I guess I'll learn all that soon enough, thanks :)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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