Convergence and Divergence of Riemann Sum Series with Varying p

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Homework Help Overview

The discussion revolves around the convergence and divergence of a series defined by a Riemann sum involving logarithmic functions and a parameter p. Participants are exploring the conditions under which the series converges for values of p greater than zero.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the potential use of the integral test for convergence and suggest bounding the series with another series. Questions are raised about the instructor's claim of divergence for all p and the implications of undefined terms in the series.

Discussion Status

The conversation is ongoing, with some participants offering guidance on approaches like the integral test and questioning the initial conditions of the series. There is no explicit consensus on the convergence behavior, as different interpretations and methods are being explored.

Contextual Notes

There are concerns about the definition of the series at certain points, particularly regarding the behavior of logarithmic terms at n=1 and n=2, which may affect the analysis of convergence.

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For what values of p>0 does the series

Riemann Sum [n=1 to infinity] 1/ [n(ln n) (ln(ln n))^p]

converge and for what values does it diverge?

How do i do this question? Would somebody please kindly show me the steps? Do i use the intergral test?
 
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Try bounding it by the series 1/n^(1+e), e>0. Note these sums get arbitrarily large as e->0.
 
it is actually a example question, my instructor said that it is divergent for all p, but i don't get it because actually i didn't copy all of the notes. Do you mind explaining it to me?
 
Last edited:
Oh, actually the integral test does work. You can do it nicely with a substitution. Also, be careful with the first two terms. ln(ln(1))=-infinity and ln(1)=0, so the first term isn't well defined, but even if you take the limit it blows up. And ln(ln(2)) is negative, and so can't be raised to the pth power in a well defined way. I would assume the series is supposed to start at n=3.
 
Last edited:

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