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I'm preparing for my quantum mechanics test. In the solutions of an old test I find this conversion, that I don't understand.

[tex] \Psi = Nze^{-r/2a_0} = Nre^{-r/2a_0}cos\Theta[/tex]

N is the normalization constant, which is to be calculated. I would have guessed that z is the atomic number ( =1), but it is apparently [tex] = r cos \Theta [/tex]. Can anyone please explain this to me?

Best regards,

Alfred