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Conversion of hydrogen atom wave function that I don't understand

  • Thread starter adh2
  • Start date
  • #1
5
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Hello!

I'm preparing for my quantum mechanics test. In the solutions of an old test I find this conversion, that I don't understand.

[tex] \Psi = Nze^{-r/2a_0} = Nre^{-r/2a_0}cos\Theta[/tex]

N is the normalization constant, which is to be calculated. I would have guessed that z is the atomic number ( =1), but it is apparently [tex] = r cos \Theta [/tex]. Can anyone please explain this to me?

Best regards,
Alfred
 

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
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Welcome to PF!

Hello Alfred! Welcome to PF! :wink:

I'm guessing :redface:, but it looks as if z is the component in the z-direction, and r and θ are the usual spherical coordinates, so that z = rcosθ. :smile:
 
  • #3
5
0
Yes! That's it. Many thanks Tiny-Tim! :smile:
 

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