Convert 730 mmHg to Pascals: Solve the Question

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The discussion centers on converting atmospheric pressure from 730 mmHg to Pascals. The user initially calculated the pressure using the formula 1 atm = pgh, resulting in an answer of approximately 97,325.06 Pa when using the conversion factor of 133.322 Pa/mmHg. However, the study guide states the answer as 96,000 Pa, leading to confusion. The community suggests that the user's method is valid, and the discrepancy may arise from rounding or different assumptions in the study guide.

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if atmospheric pressure is 730mm of mercury, what is this in pascals..?

based on my study guide 1atm = pgh

= 13,590 kg/m(cube) * 9.807 N/kg * 0.76m

= 101,300Pa

do i calculate it as such :

= 13,590 kg/m(cube) * 9.807 N/kg * 0.73m...?

my answer does not tally as the guide's answer states 96000Pa

i even tried by g = 10N/kg instead of 9.807 (if less accuracy is needed)...
but my answer still does not tally..? i'll be able to find the pressure in atmospheres and millibars once i obtain the calculating method to the first problem...pls help !
 
Last edited:
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There are 133.322 pascals per mm of mercury
 
thx you so very much for the quick reply...by multiplying 133.322 pascals to 730mm (mercury) i obtained the answer 97,325.06 pascals which very close to the method i first used in the previous post (97,292.3049 pascals).
why does my study guide state 96,000 pascals as the answer ? I'm so sorry but i have no tutor and i study by myself (very new to physics)...thx you!
 
I don't quite know
 
ok thanks so much though...last question...the method that i used (first post)..is it also considered a correct way of finding the answer..? are you a moderator..? should i leave this post as it is hoping someone else might be able to answer it or should i close this post once you reply to it (the 'last question')..? sorry for the trouble...thx!
 
Im not a moderator, it is a good idea to leave the post open as people have different specialities and are more qualified than me to answer your question, after all I am mearly a student! Your method looks fine and as the two answer are in close agreement I would expect them to be right. Check back soon to see if anyone else has added to your post.
 
Forces & Pressure (Homework Question)

thank you so much ! i appreciate your assistance.

can anyone pls help me figure out why my study guide states a different answer. thanks !
 
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