Convert nitrate standard of 50 ppm to its nitrogen content

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SUMMARY

The discussion focuses on converting a nitrate standard of 50 ppm to its nitrogen content. The molar mass of nitrate (NO3) is calculated as 62.01 g/mol, with nitrogen contributing 14.01 g/mol. The conversion formula used is (14.01/62.01) * 50 ppm, resulting in a nitrogen concentration of approximately 11 ppm. The multiplication by 10 in the original equation is clarified as unnecessary for this conversion.

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Frankenstein19
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Homework Statement


Convert the nitrate standard of 50 ppm to its nitrogen content

Homework Equations


Since NO3 contains one nitrogen, molar mass 14.01, in a total molar mass of 14.01 + (3 *16.00) = 62.01, the maximum concentration permitted expressed as nitrate ion itself is (62.01/14.01) *10= 44 ppm

This is what's in my books and I THINK it pertains to the question, however, I don't know why its being multiplied by 10 at the end.

The Attempt at a Solution


My guess would be that it would be 50ppm divided by the maximum concentration permitted, so 50/44=1.136, but that's wrong since my books says it's 11ppm. Unless I need to multiply by that mysterious 10...
 
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First of all - it is not clear to me how to understand "the nitrogen content".

But in general, assuming it just means concentration of nitrogen in ppm, none of the approaches listed makes sense to me. Yes, there are 14 g of nitrogen per 62 g of nitrate ion, so if there is 50 ppm of nitrate, concentration of nitrogen is 14/62*50 ppm. Nothing more fancy.
 

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