1. The problem statement, all variables and given/known data The nitrate concentration in an aquifer is 20 ppm, and its volume is ten million liters. What mass of ammonia upon oxidation would have produced this mass of nitrate? [Hint: The moles of nitrogen in reactant and product are identical.] 2. Relevant equations Possibly 1mg/L & NH3+O2---->NO3- 3. The attempt at a solution Since 1mg/L equals 1ppm then I'd get a 2*10^8mg for nitrate mass. And NH3+O2---->NO3- (through aerobic contitions and nitrification, idk if this is applicable >: ) then the 1:1 ratio means there's an equal amount of ammonium?