Converting an Equation to Neutral Form

[1question]

Homework Statement

Hi. I have convert the following equation (which is in ionic form) into neutral form:
4S₂O₃^2-+O₂+2H₂O=2S₄O₆^2-+4OH^-

The question tells me to use calcium as a counterion for all anions.

Homework Equations

N/A

The Attempt at a Solution

I basically just added calcium to the anions above, resulting in:
4CaS₂O₃+O₂+2H₂O=2CaS₄O₆+4Ca(OH)₂

Unfortunately, when I do a check, the coefficients of each element/compound do not match. Trying to balance it doesn't work.

 

[Borek]

4CaS₂O₃+O₂+2H₂O=2CaS₄O₆+4Ca(OH)₂

Looks balanced to me. Can you show where the mismatch is?

 

[1question]

Turns out that it's 2Ca(OH)₂. It seems obvious in hindsight haha. The number of hydroxides must remain the same as in the ionic form after all.

 

[Borek]

Sorry, I am blind. Sigh.

 

[1question]

Haha, don't worry about it. I stared at it for a good 15 minutes before I figured it out.