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Converting an Equation to Neutral Form

  1. Oct 9, 2014 #1
    1. The problem statement, all variables and given/known data

    Hi. I have convert the following equation (which is in ionic form) into neutral form:
    4S2O32-+O2+2H2O=2S4O62-+4OH-

    The question tells me to use calcium as a counterion for all anions.
    2. Relevant equations

    N/A

    3. The attempt at a solution

    I basically just added calcium to the anions above, resulting in:
    4CaS2O3+O2+2H2O=2CaS4O6+4Ca(OH)2

    Unfortunately, when I do a check, the coefficients of each element/compound do not match. Trying to balance it doesn't work.
     
  2. jcsd
  3. Oct 10, 2014 #2

    Borek

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    Staff: Mentor

    Looks balanced to me. Can you show where the mismatch is?
     
  4. Oct 11, 2014 #3
    Turns out that it's 2Ca(OH)2. It seems obvious in hindsight haha. The number of hydroxides must remain the same as in the ionic form after all.
     
  5. Oct 12, 2014 #4

    Borek

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    Staff: Mentor

    Sorry, I am blind. Sigh.
     
  6. Oct 12, 2014 #5
    Haha, don't worry about it. I stared at it for a good 15 minutes before I figured it out.
     
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