Converting Electron Mass from kg to MeV/c^2: A Quick Guide

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SUMMARY

The conversion of electron mass from kilograms to MeV/c² utilizes Einstein's equation E=mc². The mass of an electron is approximately 9.11 x 10^-31 kg, which translates to an energy of 0.512 MeV when calculated using the speed of light (3.0 x 10^8 m/s). The conversion involves first calculating the energy in joules and then converting joules to electronvolts, where 1 eV equals 1.602 x 10^-19 joules. The final expression for the mass of an electron in MeV/c² is 0.512 MeV/c².

PREREQUISITES
  • Understanding of Einstein's equation E=mc²
  • Knowledge of energy conversion from joules to electronvolts
  • Familiarity with the mass of an electron (9.11 x 10^-31 kg)
  • Basic understanding of the speed of light (3.0 x 10^8 m/s)
NEXT STEPS
  • Learn detailed calculations involving E=mc² for other particles
  • Research the implications of mass-energy equivalence in particle physics
  • Explore energy conversion factors between joules and other units
  • Study the significance of MeV/c² in high-energy physics
USEFUL FOR

This discussion is beneficial for physics students, researchers in particle physics, and anyone interested in understanding mass-energy conversion and its applications in theoretical physics.

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how do you change the measurement unit for an electron mass from kg to MeV/c^2?
 
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use Einstein's famous equation
E=mc^2
and use the conversion for joules per electron volt.
 
thanks! :)
 
It is a pleasure.
 
@@a I'm still having trouble doing the calculations~
could you write out the whole equation to transfer the mass of an electron from kg to Mev?
 
You know the mass of the electron and you know the speed of light. Just plug those into E=mc^2. You will have an energy value in terms of joules. Since you also know that one electronvolt is equivalent to 1.602*10^-^1^9 joules, you can find the energy value in terms of electronvolts instead. Rearrange the original expression and you can reexpress the mass in terms of MeV/c^2.
 
Last edited:
It is amazing how much confusion such a deceptively simple formula can generate. First calculate the rest mass of an electron:
\begin{split*} E_e = m_ec^2 \\<br /> \ = 9.11 \times 10^{-31} \times (3.0 \times 10^8)^2 \\<br /> \ = 8.2 \times 10^{-14} \ joule \\<br /> \ = 512 \ keV \\<br /> \ = 0.512 \ MeV \\<br /> \ m_ec^2=0.512 \ MeV\end{split*}
Now get the mass in the "strange" new units:
m_e=0.512 \ MeV/{c^2}
 
Last edited:
thank you very much! :)
 

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