(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A piece of gold leaf (density 19.3 g/cm^3) weighing 1.93 mg can be beaten into a transparent film covering an area of 14.5 cm^3. what is the volume of 1.93 mg of gold? What is the thickness of the transparent film in angstroms? I only need help with the second question. The volume of 1.93 mg of gold is 10^(-4) cm^3, but I don't know how to convert to length on the second question.

2. Relevant equations

Angstrom=10^(-10) meters

d=mass over volume

3. The attempt at a solution

I tried to cheat by taking the third root of 14.5 cm^3 in order to get to cm:

(14.5cm^3)^(1/3)=2.44 cm

2.44 cm (10^(-2)m/1cm)(1 Angstrom/10^(-10) meters)= 2.44 x 10^8 anstroms

The answer is 690 angstroms though and i don't know how

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# Homework Help: Converting from mass/volume to length

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