1. The problem statement, all variables and given/known data Gold, which has a density of 19.32 g/cm3, is the most ductile metal and can be pressed into a thin leaf or drawn out into a long fiber. (a) If a sample of gold with a mass of 4.713 g, is pressed into a leaf of 6.549 μm thickness, what is the area of the leaf? (b) If, instead, the gold is drawn out into a cylindrical fiber of radius 2.400 μm, what is the length of the fiber? 2. Relevant equations d=m/v, V=(l)(w)(h) V=pi(r^2)h 3. The attempt at a solution Part A.] First I found the volume by dividing 4.713g by 19.32g to get 0.2439cm^3. Then I converted 6.549μm to cm: (6.549μm)(1cm/10000μm)=6.549cm Then I solved for area by dividing (0.2439cm^3) by (6.549E-4) and got 372.49cm^2 Then I converted 372.49cm^2 to m^2 by dividing by 100 and got 3.72m^2 for the area.(But my online homework said this was wrong) Part B.]I converted the radius 2.400μm to 2.4E-4cm, squared 2.4E-4cm, then multiplied by pi, and divided the volume from part A (0.2439cm^3), and solved for the height and got 1327843.425cm and converted to 13478.43m , which seems really wrong... Please help, I can't figure out what I'm doing wrong.