Converting potential energy to force

Click For Summary
SUMMARY

The discussion focuses on converting potential energy into impact force during an impact test involving a metal ball falling onto a plastic surface. Participants suggest using Timoshenko's deflection formula, \delta = \sqrt{\frac{Wv^2L^3}{2g*24*EI}}, to estimate deflection and derive impact force. They emphasize the importance of measuring static deflection and using the formula F = m*g*[1 + (1 + 2*h/delta)^0.5] for accurate calculations. The conversation highlights the challenges of estimating impact force without proper instrumentation like strain gauges or accelerometers.

PREREQUISITES
  • Understanding of potential energy and its conversion to kinetic energy
  • Familiarity with beam deflection theory and formulas
  • Knowledge of impact testing principles and methodologies
  • Experience with instrumentation techniques such as strain gauges or accelerometers
NEXT STEPS
  • Research Timoshenko's beam theory and its applications in impact testing
  • Learn how to calculate static deflection using classical beam theory
  • Explore the Charpy impact test and its relevance to material toughness
  • Investigate methods for measuring deflection and strain in structural components
USEFUL FOR

Engineers, material scientists, and researchers involved in impact testing, structural analysis, and material performance evaluation will benefit from this discussion.

assafwei
Messages
20
Reaction score
0
Hi,

I have an impact test (Metal ball falling on plastic) and i have a problem conveting the energy (i.e. height and mass) to the force apllied to the plastic upon impact.

I tried calculating with impact formulas but its difficult to estimate the time interval of the impact.
I tried derivating energy by length (F=dU/dx) but the results seems way off.

Any ideas?

Thanks,

Assaf.
 
Engineering news on Phys.org
Do a google search for force of falling objects. I'm 98% sure there are equation in the Roark handbook, but I'm not sure where my copy is at the moment. If I can find it, I'll post it.

Also try searching here, I'm pretty sure it's been discussed a couple of times here.
 
Timoshenko is the only one that I know of that talks about the deflection/force due to a dropped object, but it is on a simply supported beam. Everyone else seems to skip the load and go directly to calculating stresses. If you can arrange your set up to be just that, you can measure the deflection of the beam at the mid span and use

\delta = \sqrt{\frac{Wv^2L^3}{2g*24*EI}}

Where

W = weight of the falling object
L = span length
v = speed of the object at impact, i.e. v=\sqrt{2gh}

Calculate that and then go back and compare that to the static load required to bend the same beam under static, classical beam theory.

This does assume that all potential energy goes into the deflection of the beam. Of course we know that this is not going to be true. So this calculation would be a maximum.

Without instrumenting your set up with either strain gauges or accelerometers, getting an accurate result is very very difficult (as you have found out).
 
FredGarvin said:
Timoshenko is the only one that I know of that talks about the deflection/force due to a dropped object, but it is on a simply supported beam. Everyone else seems to skip the load and go directly to calculating stresses. If you can arrange your set up to be just that, you can measure the deflection of the beam at the mid span and use

\delta = \sqrt{\frac{Wv^2L^3}{2g*24*EI}}

Where

W = weight of the falling object
L = span length
v = speed of the object at impact, i.e. v=\sqrt{2gh}

Calculate that and then go back and compare that to the static load required to bend the same beam under static, classical beam theory.

This does assume that all potential energy goes into the deflection of the beam. Of course we know that this is not going to be true. So this calculation would be a maximum.

Without instrumenting your set up with either strain gauges or accelerometers, getting an accurate result is very very difficult (as you have found out).

From what i understood, you propose to calculate the deflection using your equation and then extract the force using regular beam deflection equations?
This could be feasble assumin I am trying to figure out the force exerted on a beam, unfortunatley this is not the case...

I was pretty sure there is a simple way of converting potential energy to force on impact...
 
assafwei said:
I was pretty sure there is a simple way of converting potential energy to force on impact...
There isn't. Force and energy are entirely different animals and not directly related. Impact force depends on the deformation and resulting deceleration. You may want to look up a charpy impact test and fracture toughness for more info. Ie, steel can handle a lot more force than aluminum, but breaks under impacts where aluminum won't due to the fact that it is less ductile and doesn't deflect when a force is applied.
 
assafwei: Is your metal ball falling on a plastic plate? Is it a structural component such that you could measure or calculate a static deflection? If so, measure or calculate the static deflection, delta, of your plastic plate when you place the metal ball on the plate. Then, assuming your plate remains in the elastic range during the impact, you can compute the impact force F = m*g*[1 + (1 + 2*h/delta)^0.5], where m = falling object mass, h = drop height, and delta = static deflection. This is an estimate.
 
nvn said:
assafwei: Is your metal ball falling on a plastic plate? Is it a structural component such that you could measure or calculate a static deflection? If so, measure or calculate the static deflection, delta, of your plastic plate when you place the metal ball on the plate. Then, assuming your plate remains in the elastic range during the impact, you can compute the impact force F = m*g*[1 + (1 + 2*h/delta)^0.5], where m = falling object mass, h = drop height, and delta = static deflection. This is an estimate.

Unfortunbatley i don't have the equipment to measure the deflection so this method is not applicable
 
FredGarvin,

Can you please tell in which book Timoshenko mentions this formula?

Can you tell the assumptions behind this? What is "span length"? And is there any assumption on the geometry of the falling object and the region on the beam at which it falls? And why does v = 0 lead to zero deflection (because even if we just place a weight W on the beam, it'll deflect at the midspan).

Srikant
 
I would do this. I would drop the ball on a cantilever beam. Then I would instrument the beam to tell me the deflections and strain it sees due to impact. I would then hit the beam with a force hammer until I got the same response as the ball caused. Bingo you're done.
 
  • #10
I have put together the attached spreadsheet for calculating the impact force of a dropping object. You'll have to approximate the deflection of the plastic case due to impact force and you'll be able to calculate the impact force.

At the least you can get a range of forces starting from zero deflection-bigger force to maximum deflection smaller force.

I hope it helps.

Tudor Agapescu
 

Attachments

Last edited:

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 24 ·
Replies
24
Views
4K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K