Converting Redshift to Velocity: The Accurate Formula Explained

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Discussion Overview

The discussion centers around the formula used to convert redshift into velocity, specifically seeking a general and accurate formula rather than the low-speed approximation. Participants explore different contexts, including special relativity and cosmology, and the implications of various formulas in these frameworks.

Discussion Character

  • Debate/contested
  • Technical explanation
  • Conceptual clarification

Main Points Raised

  • Some participants inquire about the appropriate formula for converting redshift to velocity, distinguishing between special relativity and cosmology.
  • One proposed formula is v=[((1+z)^2-1)/((1+z)^2+1)]c, which is linked to Hubble's Law.
  • Another participant challenges the correctness of the proposed formula, suggesting that for a zero density universe, the relationship is v=H_{0}D, with D=(c/H_{0})ln(1+z).
  • There is mention of a paper that provides a general formula, with participants referencing specific equations from it.
  • Some participants express frustration with the debate over cosmological redshift interpretations, noting differing views among cosmologists.
  • It is noted that the conventions for distance used in different formulas lead to varying expressions for speed.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct formula for converting redshift to velocity, with multiple competing views and interpretations remaining unresolved.

Contextual Notes

Discussions highlight the dependence on specific cosmological models and assumptions, as well as the differing conventions used in the formulas presented.

TrickyDicky
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What is the formula used to convert the measured redshift into a velocity?, not the approximated formula for low speeds v=cz , but the more general and accurate one.

Thanks.
 
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TrickyDicky said:
What is the formula used to convert the measured redshift into a velocity?, not the approximated formula for low speeds v=cz , but the more general and accurate one.

Thanks.
Do you want the answer for special relativity or cosmology or both?
 
Passionflower said:
Do you want the answer for special relativity or cosmology or both?

For cosmology, the one used to get a velocity from the redshift and plug it in the Hubble Law formula.
 
TrickyDicky said:
For cosmology, the one used to get a velocity from the redshift and plug it in the Hubble Law formula.

I think , this is the one

v=[((1+z)^2-1)/((1+z)^2+1)]c=Ho*D

c=light speed constant
Ho=Hubble constant
D=distance
v=velocity
 
TrickyDicky said:
I think , this is the one

v=[((1+z)^2-1)/((1+z)^2+1)]c=Ho*D

c=light speed constant
Ho=Hubble constant
D=distance
v=velocity

No, this isn't correct. See section 3 from

http://arxiv.org/abs/astro-ph/0310808.

It is fairly easy to derive equation (1) from this paper.
 
TrickyDicky said:
I think , this is the one

v=[((1+z)^2-1)/((1+z)^2+1)]c=Ho*D

c=light speed constant
Ho=Hubble constant
D=distance
v=velocity

I don't think it is correct. For zero density universe it is:

v=H_{0}D

D=(c/H_{0})ln(1+z)
 
George Jones said:
No, this isn't correct. See section 3 from

http://arxiv.org/abs/astro-ph/0310808.

It is fairly easy to derive equation (1) from this paper.

The one I wrote is exactly equation (2) from that paper.

Calimero said:
I don't think it is correct. For zero density universe it is:

v=H_{0}D

D=(c/H_{0})ln(1+z)
This is not exactly what I wanted. I asked for the way to translate from z to velocity for high z or at least >1, this must be a very common formula for cosmologists, I'd say.
The formula I used maybe is not correct for the Hubble law but I'm interested in the first part, express v as a function of z, is that so difficult?
 
Ok, I see what you mean, after looking at the paper and the formula again, I see what you mean, but according to some cosmologists the formula that doesn't give superluminal velocities is alright too, and anyway this is a cosmology debate that I find artificial and tiresome and I don't really want to get into it , I think it's been discussed enough in these forums, just remember that people as prestigious as David Hogg supports the view of cosmological redshift as Doppler.
 
  • #10
TrickyDicky said:
The one I wrote is exactly equation (2) from that paper.

Yes, but this is not the correct equation to use for cosmology.
Calimero said:
I don't think it is correct. For zero density universe it is:

v=H_{0}D

D=(c/H_{0})ln(1+z)

This expression and the expression that TrickyDicky gave in post #5 are both true in special relativity, i.e., in an empty universe. The conventions used for distance, however, are different in posts #5 and #7, and this leads to differing expressions for speed.
 
  • #11
George Jones said:
This expression and the expression that TrickyDicky gave in post #5 are both true in special relativity, i.e., in an empty universe. The conventions used for distance, however, are different in posts #5 and #7, and this leads to differing expressions for speed.

Yes, for empty universe D=(c/H_{0})ln(1+z) gives distance that goes into Hubble's law. Equation (1) you pointed at is general one, and \dot{R} would depend on particular values of \Omega_{\lambda} and \Omega_{m} you choose.
 
Last edited:
  • #12
TrickyDicky said:
...and anyway this is a cosmology debate that I find artificial and tiresome and I don't really want to get into it , I think it's been discussed enough in these forums, just remember that people as prestigious as David Hogg supports the view of cosmological redshift as Doppler.


What debate?

TrickyDicky said:
What is the formula used to convert the measured redshift into a velocity?, not the approximated formula for low speeds v=cz , but the more general and accurate one.

TrickyDicky said:
For cosmology, the one used to get a velocity from the redshift and plug it in the Hubble Law formula.
 

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