Convolution and Impulse Signals

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Convolution involves multiplying two signals and integrating the result, but confusion arises regarding its commutative property. When convolving two general functions, such as x(t) = sin(t) and h(t) = t^2, different results can occur if the time-shift is altered, challenging the expectation of commutativity. However, the commutative property holds true when one of the functions is an impulse signal. This raises the question of whether convolution is primarily applicable between an impulse and a generic signal rather than between two generic signals. Clarification on this topic can be found in resources discussing the symmetric nature of convolutions.
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I am a little confused about convolutions.

I know that convolution is the multiplication and then integral of the two signals. The confusion starts at the commutative property. If i try to change the time-shift from signal to another for any 2 general functions or equations the commutative property doesn't work out.

for example:
let x(t) = sin(t)
and h(t) = t^2

If you try to convolve the signals above with the commutative property you get 2 different results.

However, the convolution's commutative property does work out if h(t) were to be a impulse function. So, does it mean that convolution is only an integral between an impulse signal and a generic signal and not two generic signals? (which is the part i am confused because i have seen examples of convolving 2 different signals)
 
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I'm not sure what you are referring to. This article shows how convolutions are symmetric
http://en.wikipedia.org/wiki/Convolution"
Scroll down to "Definitions" for the commutative property.
 
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