Coordinate singularity in Schwarzschild solution

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The discussion revolves around the Schwarzschild solution's line element, which presents an apparent singularity at r=0. Participants clarify that this singularity is likely a coordinate singularity, suggesting that the problem statement should refer to r=2m instead. The key task is to treat τ as an angular coordinate, which requires it to be confined to the range from 0 to 2π. This approach helps in demonstrating that the singularity is not physical. The conversation emphasizes the importance of understanding the metric's properties and the implications of changing the variable τ.
Confused Physicist
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Hi! I have the following problem I don't really know how to approach. Could someone give me a hand?

The line element of a black hole is given by: ds^2=\Bigg(1-\frac{2m}{r}\Bigg)d\tau ^2+\Bigg(1-\frac{2m}{r}\Bigg)^{-1} dr^2+r^2\Big(d\theta ^2+\sin^2(\theta)d\phi ^2\Big)

It has an apparent singularity at ##r=0##. By making ##\tau## an angular coordinate, show that this singularity is a coordinate singularity (not physical) and find the period of ##\tau## that makes it possible. (consider expanding the metric functions about ##r=2m##).

Thanks for the help!
 
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Confused Physicist said:
The line element of a black hole

Note that this is not the usual Schwarzschild metric; there is no minus sign in front of the first term on the RHS. (If there were, the question would not make sense because ##\tau## would not be able to be treatd as an angular coordinate.)
 
@Confused Physicist I have moved this thread to the homework forum. You will need to at least show some attempt at a solution. You could start by taking the hint in the parenthetical in the OP.
 
Confused Physicist said:
It has an apparent singularity at ##r=0##. By making ##\tau## an angular coordinate, show that this singularity is a coordinate singularity

Are you sure the problem statement says ##r = 0## and not ##r = 2m##?
 
PeterDonis said:
Are you sure the problem statement says ##r = 0## and not ##r = 2m##?

Thanks PeterDonis, I will post my future questions in the homework forum. I've been trying to squeeze my head around it, but I haven't posted my attempt because I literally don't have a decent one.

Yes, the problem says ##r=0##, but you're right. I believe it's a mistake and it should say ##r=2m##.
 
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PeterDonis said:
Note that this is not the usual Schwarzschild metric; there is no minus sign in front of the first term on the RHS. (If there were, the question would not make sense because ##\tau## would not be able to be treatd as an angular coordinate.)

What does it mean to treat ##\tau## as an angular coordinate? Is it a specific change of variable?
 
Confused Physicist said:
What does it mean to treat ##\tau## as an angular coordinate?

It means it only covers the range ##0## to ##2 \pi## instead of ##- \infty## to ##+ \infty##.