B Copenhagen Interpretation and collapse moment

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Under the Copenhagen Interpretation (CI) of quantum mechanics (QM), a measurement apparatus does not enter a superposition of states, contrasting with the Many-Worlds Interpretation (MWI). The CI asserts that a single measurement result is obtained when the Born rule is applied during a measurement, but it does not explain the mechanism behind achieving a decisive outcome. While the CI clarifies that a decisive outcome occurs upon measurement, it leaves the "how" of the process ambiguous. The randomness of outcomes, such as in decay times, is acknowledged but not fully explained within the CI framework. This highlights the ongoing complexities and discussions surrounding the measurement problem in quantum mechanics.
entropy1
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Is it still true that under the Copenhagen Interpretation the standard theory of QM tells us that a measurement apparatus gets into superposition of possible measurement outcomes and does not tell us how and when we get a single decisive outcome? (The so-called "Measurement problem")
 
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entropy1 said:
Is it still true that under the Copenhagen Interpretation the standard theory of QM tells us that a measurement apparatus gets into superposition of possible measurement outcomes and does not tell us how and when we get a single decisive outcome?
This is what the MWI says. The CI assumes the measurement apparatus is never in a superposition of states. It says you get a single measurement result when you apply the Born rule(and do a measurement).
 
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entropy1 said:
does not tell us how and when we get a single decisive outcome?
It doesn't tell how, but it does tell when. It's when a measurement is performed. Now if you wonder how then the time of decay is random, see my https://arxiv.org/abs/2010.07575 .
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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