Copper Solubility in Water with pH 5

Click For Summary

Discussion Overview

The discussion revolves around calculating the solubility of copper in water with a pH of 5, specifically focusing on the corrosion of a copper pipe at 25 °C. Participants explore the application of the Nernst equation and the implications of reduction potentials in this context.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a task involving the calculation of copper solubility using the Nernst equation and expresses difficulty in reaching a solution.
  • Another participant suggests writing Nernst equations for both half cells, indicating that at equilibrium, the reduction potentials will be identical, and proposes that the concentration of copper is the unknown.
  • A different participant expresses skepticism about the previous suggestion, indicating confusion regarding the relevance of pH and the stated reduction potential.
  • One participant outlines the steps they took to derive a potential cell reaction and calculates the concentration of copper ions, but expresses doubt about the correctness of their result.
  • Another participant revisits the initial question and questions the clarity of the problem, suggesting that pH may not be relevant and that the solution could be approached by focusing solely on the reduction potential of copper.

Areas of Agreement / Disagreement

Participants exhibit disagreement regarding the relevance of pH in the calculations and the interpretation of the problem statement. There is no consensus on how to proceed with the calculations or the assumptions that should be made.

Contextual Notes

Participants note potential confusion regarding the significance of pH and the reduction potential, as well as the assumptions made in applying the Nernst equation. There are unresolved questions about the correct approach to the problem.

Kristina_elt
Messages
3
Reaction score
0
Hello,

I have a problem with this task:

"Water with pH 5 and reduction potential +0.30 V flows through copper pipe at 25 °C. Calculate how much copper dissolves (in ppm) in water due to corrosion of this pipe. Standard reduction potential of copper Cu0/Cu2+ is 0.34 V."

I spent lot of hours with lot of calculations without any glory :( Please, is there anybody who could try to help me?

This figure could be helpful:

http://www.advancedaquarist.com/2003/5/chemistry_album/figure3.gif

I tried to use Nernst equation:

Eh = E0 - (RT / nF)*(lnQ).

The main equation I used was:

Cu + 2H+ -> Cu2+ + H2.
 
Physics news on Phys.org
Write Nernst equations for both half cells. At the equilibrium both reduction potentials will be identical. Potential of the hydrogen cell is easy to calculate, that leaves you with just one unknown - concentration of the copper.
 
I do not think so :( ...
 
Have you tried to follow what I wrote?

If so, can you show the steps?
 
Borek said:
Have you tried to follow what I wrote?

If so, can you show the steps?

Ok. Firstly I wrote this:

Cu -> Cu2+ + 2e- (E0 = -0.34 V)
H2 -> 2H+ + 2e- (E0 = 0.00 V)

The following reaction was:

Cu + 2H+ -> Cu2+ + H2 (E0 cell = 0.34 V)

Next step:

0.3 V = 0.34 V - (RT / 2F) * ln ([Cu2+] / [10^-10])

Then I got:

3.11 = ln ([Cu2+] / [10^-10])

And for [Cu2+]:

22.42 * 10^-10 = approx. 2.24E-09

In ppm:

2.24E-09 * 1000 * 63.5 = 1.42E-04 ppm (I think this result is incorrect)
 
Sorry. On the second read question no longer makes any sense to me. Apparently I was way too fast in my answer now (and I realized why I didn't answer the first time I have seen the question elsewhere).

I have no idea what they mean by "Water with pH 5 and reduction potential +0.30 V". Unless pH is completely irrelevant and the only thing that is important is the potential - regardless of its source (most likely some not mentioned, but present, redox system). If so, question can be solved by ignoring pH (just by applying Nernst equation to copper). If not - I have no idea what to do.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 11 ·
Replies
11
Views
7K
  • · Replies 7 ·
Replies
7
Views
7K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 2 ·
Replies
2
Views
6K
  • · Replies 2 ·
Replies
2
Views
4K