Coriolis acceleration and magnitude question

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Homework Help Overview

The discussion revolves around the calculation of Coriolis acceleration for an airplane flying at a constant altitude over London, specifically addressing its magnitude and direction. The problem is situated within the context of rotational dynamics and the effects of Earth's rotation on moving objects.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the formula for Coriolis acceleration and question the correct interpretation of the angular velocity. There is uncertainty about how to incorporate the latitude of London into the calculations and the application of the right-hand rule for determining direction.

Discussion Status

Some participants have provided clarifications regarding the formula and the role of latitude, while others express confusion about the direction of the Coriolis acceleration. Multiple interpretations of the problem are being explored, and guidance has been offered without reaching a consensus.

Contextual Notes

Participants are navigating through the complexities of the Coriolis effect, with specific attention to the implications of latitude and the right-hand rule. There is an acknowledgment of the need for further exploration of these concepts without definitive resolutions presented.

P-Jay1
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Q. An aeroplane flies at constant altitude due south over London. Its speed is 320 km/h and the latitude of London is 51 degrees North. What is the magnitude and direction of the Coriolis acceleration on the aeroplane?


Do I use Coriolis acceleration = 2ω x v to find acc? Is ω = 2π / 24 x60 x60 ??
What is the direction?
 
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hi P-Jay1 ! :smile:
P-Jay1 said:
Do I use Coriolis acceleration = 2ω x v to find acc? Is ω = 2π / 24 x60 x60 ??
What is the direction?

actually it's minus 2ω x v

(and yes, = |ω| = 2π / 24 x60 x60)

to find the direction of https://www.physicsforums.com/library.php?do=view_item&itemid=86", remember that velocity (of a fixed point on the Eartth) = ω x r, so that'll help you to work out the direction! :wink:
 
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Hey Tim!

That's cleared up a few things.. still a bit confused about the direction though. I'm not sure where the latitude of London comes in.

Do I use ω x r = ωrsinθ ? Do I use the right hand rule? The plane is in the Northern hemisphere, but traveling south, so is direction of Coriolis acceleration east to west?
 
P-Jay1 said:
I'm not sure where the latitude of London comes in.

That helps you find θ. :wink:
Do I use ω x r = ωrsinθ ? Do I use the right hand rule? The plane is in the Northern hemisphere, but traveling south, so is direction of Coriolis acceleration east to west?

|ω x v| = ωvsinθ.

As to the rest, you're on your own … I don't want to muddle my brain up trying to work it out! :biggrin:
 

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