Cosine Rule Help: Solving the Cut Size of a Curved Bar

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SUMMARY

The discussion focuses on calculating the cut size of a curved bar using the cosine rule and arc length formulas. The chord length is 650mm, and the radius is 1335mm, leading to the calculation of the inner angle, which is determined to be 28.17°. The final arc length is calculated as 656mm, confirming that the initial calculations were accurate. The user expresses gratitude for the assistance in applying trigonometric concepts to their work.

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Homework Statement



Hello! I've run into a problem at work and need a quick solution! Basically I need to work out the cut size of a curved bar. I have the chord length (650mm) and the radius' (1335mm) Obviously i need to calculate the inner most angle, then multiply my diameter by pi, divide by 360 then multiply by my new found angle to find arc length



Homework Equations



Cosine rule A=b[itex]^{2}[/itex]+c[itex]^{2}[/itex]-a[itex]^{2}[/itex][itex]/[/itex]2bc

C=∏d





The Attempt at a Solution




obviously c and b are both equal at 1335mm. so the triangle becomes isosceles


Arc length = ∏x2670/360 x (1335[itex]^{2}[/itex]+1335[itex]^{2}[/itex]- 650[itex]^{2}[/itex]/2x1335x1335)[itex]^{cos-1}[/itex]

this equation leaves us at 28.17°

then (2670x∏/360)x28.17=656mm


Only 6mm gain on the arc? is this normal? please help!


many thanks, connor.
 
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I get 656.6 mm. You did it correctly.
 
thanks very much, I've never applied that sort of trigonometry to my work before, i was abit unsure! thanks very much for your help.
 

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