Could open tube and closed (at one end) tube produce the same frequency?

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Homework Help Overview

The discussion revolves around whether a flute (open at both ends) measuring 72 cm and an oboe (closed at one end) measuring 64.8 cm can produce the same musical note. Participants explore the relationship between the lengths of the tubes and the frequencies they can produce, referencing relevant equations for open and closed tubes.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss substituting the tube lengths into the equations for frequency and wavelength. There is an attempt to isolate variables and explore mathematical relationships. Questions arise about the resonant lengths and the values of n in the equations. Some participants suggest considering the ratio of harmonics between the two instruments.

Discussion Status

The discussion is ongoing, with participants offering insights and suggestions for approaching the problem mathematically. There is an exploration of ratios and harmonic relationships, but no consensus has been reached on a definitive method or solution.

Contextual Notes

Participants note the specific lengths of the instruments and their configurations (open vs. closed ends) as critical factors in the discussion. There is also mention of potential constraints regarding the use of guess and check methods versus purely mathematical approaches.

sbayla31
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Homework Statement



Is it possible for a flute (tube open at both ends) 72 cm long and an oboe (tube open at one end) 64.8 cm long to produce the same note? Prove your answer.

Homework Equations



v=f\lambda

L=(n/2)\lambda (tube open at both ends)

L=((2n-1)/4)\lambda (tube open at one end)

The Attempt at a Solution



I can sub the lengths into the latter two equations:

0.72m =(n/2)\lambda

0.648m =((2n-1)/4)\lambda

I know how to isolate \lambda and then sub in v/f for \lambda to find the frequency (the note).

I don't know what to do next :confused:
I know I could use a guess and check method, but I would prefer doing it mathematically.
Also, how do I find out what the resonant length is (n)?
 
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hi sbayla31! :smile:

i suppose you've noticed that 64.8 = 0.9*72 ? :wink:
 
sbayla31 said:


The Attempt at a Solution



I can sub the lengths into the latter two equations:

0.72m =(n/2)\lambda

0.648m =((2n-1)/4)\lambda

I know how to isolate \lambda and then sub in v/f for \lambda to find the frequency (the note).

I don't know what to do next :confused:
I know I could use a guess and check method, but I would prefer doing it mathematically.
Also, how do I find out what the resonant length is (n)?


The idea is, n is not same in the two equations. Use n and another variable (say m) and then divide. You'll find some value for the ratio n/m. All integer tuples (n,m) that satisfy the ratio, work.
 
tiny-tim said:
hi sbayla31! :smile:

i suppose you've noticed that 64.8 = 0.9*72 ? :wink:

Hmm. Does this have anything to do with the 9th harmonic of a closed tube? Or am I totally off?
 
sbayla31 said:
Is it possible for a flute (tube open at both ends) 72 cm long and an oboe (tube open at one end) 64.8 cm long to produce the same note? Prove your answer.

what is the wavelength of that note? :smile:
 
tiny-tim said:
what is the wavelength of that note? :smile:

naughty naughty, i think you gave him to much information...
 

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