Could someone help w/ a problem

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Homework Help Overview

The problem involves calculating the braking force required to stop a car with a mass of 1150 kg moving at 16 m/s within a time frame of 10 seconds. The context is rooted in concepts of kinetic energy and kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the initial setup involving kinetic energy and question the reasoning behind dividing kinetic energy by average speed. There are suggestions to consider work done to stop the car and to use kinematics to find acceleration. Some participants express confusion about the setup and seek clarification on how to proceed.

Discussion Status

The discussion is active with participants exploring different interpretations of the problem. Some guidance has been offered regarding the use of kinematics to find acceleration, and there is a recognition of the need to clarify the relationship between speed, time, and force. However, there is no explicit consensus on the approach to take.

Contextual Notes

Participants note that the problem does not provide the car's acceleration directly, but emphasize that speed and time can be used to determine it. There is a mention of the assumption that acceleration is constant during the braking process.

btkale
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Hey I thought i had this figured out but when i submitted it it was wrong.

A car with a mass of 1150 kg moves at 16 m/s. What braking force is needed to bring the car to a halt in 10s?

I set it up as
KE=1/2mv^2
=1/2(1150)(16)^2
=147200J

then v/2= 16/2=8

force= 147200/8
=18400 N

Could someone tell me what I did wrong?
Thanks
 
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btkale said:
I set it up as
KE=1/2mv^2
=1/2(1150)(16)^2
=147200J
You found the energy.

then v/2= 16/2=8
And then the average speed.

force= 147200/8
=18400 N
Huh? Why would you divide KE by average speed?

Maybe you are thinking of:
Power = Force * Speed?

If so, what is the average power required?
 
btkale said:
Hey I thought i had this figured out but when i submitted it it was wrong.

A car with a mass of 1150 kg moves at 16 m/s. What braking force is needed to bring the car to a halt in 10s?

I set it up as
KE=1/2mv^2
=1/2(1150)(16)^2
=147200J

then v/2= 16/2=8

force= 147200/8
=18400 N

Could someone tell me what I did wrong?
Thanks

:confused::confused: What equations are you using?? I don't follow your reasoning of taking half the speed and so on...
 
Umm I'm not sure. Maybe I have it set up all wrong. I just need the breaking force in Newtons.
 
We know what you need, we're trying to understand what you did. :wink:

If you weren't thinking of power, you might wish to consider how much work is required to stop the car.

Or you can use kinematics: What's the car's acceleration?
 
It doesn't give the car's acceleration
 
F = m*a

find acceleration
 
btkale said:
It doesn't give the car's acceleration
But you have speed and time--everything you need to figure out the acceleration using kinematics.
 
if the car moves at 16 m/s the the acceleration would be constant right?
 
  • #10
btkale said:
if the car moves at 16 m/s the the acceleration would be constant right?

but the car shall stop in 10s.. hence an acceleration is done.
 
  • #11
You may assume that the acceleration is constant.
 
  • #12
Ok I wrote out everything the problem has in it so how do i set it up to solve it?
 
  • #13
Did you find the car's acceleration?
 
  • #14
No could u tell me what it is or how to get it.
 
  • #15
average a = delta(V)/delta(t) , i.e. how much the velocity changes during a certain interval of time.
 
  • #16
so the acceleration would be -1.6
 
  • #17
m/s^2 , always keep the units.

so the magnitude of the force is then?
 
  • #18
so the acceleration is -1.6
 
  • #19
wait what?
 
  • #20
btkale said:
wait what?


what are you asking about?...

you can delete your double post by pressing the "edit" button then choose "delete post".

The question was what force is needed to stop the car, right?..
 
  • #21
yeah that's right, so what do i do to set it up
 
  • #22
I / we have alreade told you that...
 
  • #23
Ok so I'm not that great in Physics so do you mind drawing me a picture?
 
  • #24
------- see post #7 in this thread. -----

it is the second law:

http://en.wikipedia.org/wiki/Newton's_laws_of_motion
 

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