Couldn't find a simple way to do it

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Discussion Overview

The discussion revolves around proving the mathematical statement that if *m* is a non-negative integer, then gcd(m·a, m·b) = m·gcd(a, b). Participants express difficulty in finding a straightforward proof for this claim.

Discussion Character

  • Mathematical reasoning
  • Homework-related

Main Points Raised

  • One participant expresses a desire to prove the statement regarding gcd but finds it challenging to articulate a simple proof.
  • Another participant questions the notation used, specifically the asterisks around certain variables.
  • A subsequent post indicates a typographical error in the notation.
  • Another participant attempts to clarify a mathematical expression but does not seem to connect with the original query.
  • A later reply suggests that the previous participant should familiarize themselves with using LaTeX for clearer mathematical communication.

Areas of Agreement / Disagreement

The discussion does not reach a consensus, as participants express confusion and differing levels of understanding regarding the notation and the original proof request.

Contextual Notes

There are indications of unclear notation and possible typographical errors, which may affect the clarity of the discussion. The use of LaTeX is suggested as a means to improve communication of mathematical ideas.

Andrax
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I wanted to prove thatIf*m*is a non-negative integer, then gcd(m·a,*m·b)*=*m·gcd(a,*b) and couldn't find an easy way to do it I know it's pretty straight forward but I couldn't do it in a simple way.
 
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What are the *s supposed to be?
 
Just miss taped that
 
X(a^b) =xa^xb
 
You are still not making any sense. Try reading about using Latex on our forums.
 

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